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zheka24 [161]
2 years ago
9

If the zeros of a quadratic function are 3 and 8, what are the factors of the function? 3and (x – 3) B. (X- 8) and (x + 3) O C.

(X + 8) and (x + 3) 00. (X - 8) and (x-3) Reset Next​
Mathematics
1 answer:
bagirrra123 [75]2 years ago
7 0

Answer:  Choice D

(x - 8) and (x - 3)

===============================================

Explanation:

The term "root" is the same as "zeros of a function".

If 3 is a root, then x = 3 leads to x-3 = 0 after subtracting 3 from both sides.

If 8 is a root, then x = 8 leads to x-8 = 0 for similar reasoning

Use of the zero product property allows us to combine those two rules into the following

(x-3)(x-8) = 0

This shows that the two factors are (x-8) and (x-3)

The order of the factors doesn't matter because we can multiply two numbers in any order.

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A farmer owns a 100 acre farm and plans to plant at most three crops. The seed for crops A,B, and C costs $40, $20, and $30 per
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Answer:

The number of acre per crop for maximum profit is;

Crop A = 0 acres

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Profit, P = $26,000

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We plant A in X acres

B in Y acres and

C in Z acres

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we work A for 1·X workdays

B for 2·Y workdays and

C for 1·Z workdays

Where X + 2·Y + Z ≤ 160

$40·X for crop A

$20·Y for crop B and

$30·Z for crop C is spent whereby

$40·X + $20·Y + $30·Z ≤ $3200

The farmer makes

$100·X from crop A

$300·Y from crop B and

$200·Z from crop C

P = $100·X + $300·Y + $200·Z

Therefore, we have three equations with three unknowns solving the equations simultaneously, we have

X + Y + Z = 100....................................................(1)

X + 2·Y + Z = 160.................................................(2)

$40·X + $20·Y + $30·Z = $3200....................(3)

By subtracting equation (1) from (2) gives Y = 60 acres

Multiplying equation (1) by 40 and subtracting from (3) we  have Z = -40

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If he plants only B the farmer has 2 work day per acre and since there is a max of 160 days, he can only plant on 80 acres, therefore, total profit = $300 × 80 = $24,000

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If we remove seed A we have

Y + Z = 100....................................................(4)

2·Y + Z = 160.................................................(5)

$40·X + $20·Y + $30·Z = $3200....................(3)

Solving equation (4) and (5), we have Y = 60 acres and Z = 40 acres

Therefore, the profit becomes

$300 × 60 + $200 × 40 = $26,000.

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Answer:

Step-by-step explanation:

Okay so to find the domain and range we need to find the x values and the y values: the domain is x and the range is y. Therefore the start of our x values can be concluded as -5 and the end is 5, so our domain will be -5 < x < 5: Note, I couldn't put the less than or equal to symbol. SO now our range is the values that are up and down, the range does down at 1 and the range is the highest at 3 so we can determine the range is 1 < y < 3. This is a continuous graph, so there is continuous x values and y values in this graph, so it's simple to use the start and the end of the domain and range followed by the possible y and x values which is represented by y and x.

Hope this helps. :)

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3 years ago
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