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zheka24 [161]
3 years ago
9

If the zeros of a quadratic function are 3 and 8, what are the factors of the function? 3and (x – 3) B. (X- 8) and (x + 3) O C.

(X + 8) and (x + 3) 00. (X - 8) and (x-3) Reset Next​
Mathematics
1 answer:
bagirrra123 [75]3 years ago
7 0

Answer:  Choice D

(x - 8) and (x - 3)

===============================================

Explanation:

The term "root" is the same as "zeros of a function".

If 3 is a root, then x = 3 leads to x-3 = 0 after subtracting 3 from both sides.

If 8 is a root, then x = 8 leads to x-8 = 0 for similar reasoning

Use of the zero product property allows us to combine those two rules into the following

(x-3)(x-8) = 0

This shows that the two factors are (x-8) and (x-3)

The order of the factors doesn't matter because we can multiply two numbers in any order.

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3.3^(2x+1)-103^x+1=0 need value of x
photoshop1234 [79]

Answer:

The value of x is approximately -1.531.

Step-by-step explanation:

Let 3.3^{2\cdot x + 1}-103^{x+1} = 0, we proceed to solve this expression by algebraic means:

1) 3.3^{2\cdot x + 1}-103^{x+1} = 0  Given

2) 3.3^{2\cdot x}\cdot 3.3 -103^{x}\cdot 103 = 0 a^{b}\cdot a^{c} = a^{b+c}

3) (3.3^{x})^{2}\cdot 3.3 -\left[\left( \sqrt{103} \right)^{2}\right]^{x}\cdot 103 = 0 (a^{b})^{c} = a^{b\cdot c}

4) (3.3^{x})^{2}\cdot 3.3 - \left[\left(\sqrt{103}\right)^{x}\right]^{2}\cdot 103 = 0 (a^{b})^{c} = a^{b\cdot c}/Commutative property

5) \left[\left(\frac{3.3}{\sqrt{103}}\right)^{x}\right] ^{2}-\frac{103}{3.3} = 0 Existence of multiplicative inverse/Definition of division/Modulative property/a^{b}\cdot a^{c} = a^{b+c}

6) \left(\frac{3.3}{\sqrt{103}} \right)^{2\cdot x}=\frac{103}{3.3} Existence of additive inverse/Modulative property/(a^{b})^{c} = a^{b\cdot c}

7) \log \left(\frac{3.3}{\sqrt{103}} \right)^{2\cdot x}=\log \frac{103}{3.3} Definition of logarithm.

8) 2\cdot x\cdot \log \left(\frac{3.3}{\sqrt{103}} \right)= \log \frac{103}{3.3}     \log_{b} a^{c} = c\cdot \log_{b} a

9) 2\cdot x \cdot [\log 3.3-\log \sqrt{103}] = \log 103 - \log 3.3      \log_{b} \frac{a}{d}

10) x\cdot (2\cdot \log 3.3-\log 103) = \log 103 - \log 3.3     \log_{b} a^{c} = c\cdot \log_{b} a/Associative property

11) x = \frac{\log 103-\log 3.3}{2\cdot \log 3.3-\log 103}   Existence of multiplicative inverse/Definition of division/Modulative property

12) x \approx -1.531  Result

The value of x is approximately -1.531.

4 0
3 years ago
There are 25 trees on the Jackson’s property. Twenty percent of the trees are oak trees. Which equation can be used to find the
belka [17]

Answer:

See below

Step-by-step explanation:

Number of oak trees

=  \frac{25}{100}  \times 25 \\

7 0
3 years ago
Saving and Spending In this open response, you will be managing a checkbook and savings account.
user100 [1]

Answer:

laviña and the two girl had been on my mind

Step-by-step explanation:

laviña and the two girl had been on my mind that you add me I need to renounce I'm poor you ty

7 0
2 years ago
Rose bought a bag of potatoes for $6.00 and some granola bars for $5.25 per package. Her total bill was $74.25. How many package
neonofarm [45]

Answer:

Rose bought 14 packages of granola bars.

Step-by-step explanation:

Total bill = 1 bag of potatoes + x amount of packages of granola bars

Total bill = $74.25

1 bag of potatoes = $6.00

1 package of granola bar = 5.25

We set the equation to:

74.25 = 6.00 + 5.25x

Subtract 6.00 from both sides:

68.25 = 5.25x

Divide both sides by 5.25 to leave x by itself

68.25/5.25 = 5.25x/5.25

13 = x

This means Rose bought 13 packages of granola bars.

Let's recheck our work by inputting x = 13 into the equation:

74.25 = 6.00 + 5.25(13)

74.25 = 6.00 + 68.25

74.25 = 74.25

7 0
2 years ago
Check my last question is u want 10 pts
larisa [96]
Ok..................
4 0
3 years ago
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