All categories

3 years ago

Solve (16×^3-3×^2+43×-5)÷(×^2-2)

Mathematics

1 answer:

Oksana_A [137]3 years ago

7 0

Answer:

3872/(x^2 - 2)

Step-by-step explanation:

Simplify the following:

(16^3 - 3^2 - 5×43)/(x^2 - 2)

3^2 = 9:

(16^3 - 9 - 5×43)/(x^2 - 2)

16^3 = 16×16^2:

(16×16^2 - 9 - 5×43)/(x^2 - 2)

| 1 | 6

× | 1 | 6

| 9 | 6

1 | 6 | 0

2 | 5 | 6:

(16×256 - 9 - 5×43)/(x^2 - 2)

16×256 = 4096:

(4096 - 9 - 5×43)/(x^2 - 2)

43 (-5) = -215:

(4096 - 9 + -215)/(x^2 - 2)

4096 - 9 - 215 = 3872:

Answer: 3872/(x^2 - 2)

You might be interested in

If x/y + y/x = -1 , ( x unequal y, y unequal 0) then the value of x^2 - y^2 is?

Maurinko [17]

Take your original equation $\frac{x}{y} +\frac{y}{x} =-1$

and multiply both sides by $xy$ to remove the fractions. You are left with

$x^2+y^2=-xy$

So, $x^2+y^2=-xy$

Update: There is no numerical answer that can be found without being given a value for either x or y

3 0

4 years ago

Read 2 more answers

Find the value of X.

anastassius [24]

Answer:

839

Step-by-step explanation:

3 0

3 years ago

Find the distance between M(-2,3) and N(8,2)

AnnZ [28]

Answer:

$d=\sqrt{101}$

Step-by-step explanation:

Distance Formula: $d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Simply plug in your 2 coordinates into the distance formula to find distance <em>d</em>:

$d=\sqrt{(8-(-2))^2+(2-3)^2}$

$d=\sqrt{(8+2)^2+(-1)^2}$

$d=\sqrt{(10)^2+1}$

$d=\sqrt{100+1}$

$d=\sqrt{101}$

6 0

3 years ago

Answers need to be fractions, if they are not whole numbers. No decimals

klemol [59]

The Slope of lines parallel to line is 1/2 and the Slope of lines perpendicular to line is -2.

<h3>What is the equation of a straight line ?</h3>

An equation that can be written in the form of y = mx+c

where m is the slope of the line

and c is the intercept on y axis

The equation given in the question is

y=1/2x−7

in this the slope = 1/2

Intercept = -7

For parallel Lines

For a parallel line , the slope of the line is same

and is given by m = 1/2

For a perpendicular line

Slope will be equal to

-1/m

here -1/m = -2

Therefore the slope for perpendicular line is -2.

To know more about Straight Line equation

brainly.com/question/959487

#SPJ1

7 0

2 years ago

Find the Lateral area of a square pyramid with a slant height of 22m and a base length of 8m

Kay [80]

Answer: 352 $m^{2}$

Step-by-step explanation:

To find the Lateral area of a square pyramid , we will follow the three steps below:

1. Find the perimeter of the base

2. Multiply the perimeter by the slant height

3. Divide the result above by 2

That is :

The lateral surface area of a regular pyramid is lateral area = perimeter of base x slant height of pyramid) ÷ 2.

Applying the formula above:

1. The base is a square , therefore the perimeter of a square is 4L , That is

Perimeter = 4(8)

Perimeter = 32m

2. Perimeter x slant height , that is

32 x 22 = 704m

3. Dividing the result by 2 , we have :

704/2 = 352

Therefore , the Lateral area of the pyramid is 352 $m^{2}$

7 0

3 years ago