Answer:
Permanent migration is when someone moves from one place to another and has no plans to return to their original home. Temporary migration is limited by time. This could be for seasonal employment. Forced migration involves the migrant having no choice but to move.
<h3> the 4 types of migration?</h3>
There are four major forms of migration: invasion, conquest, colonization and emigration/immigration. Persons moving from their home due to forced displacement (such as a natural disaster or civil disturbance) may be described as displaced persons or, if remaining in the home country, internally-displaced persons.
A- Order supplies.
A veterinary practice manager is charged with the responsibilities of managing the business activities of a veterinary hospital. A practice manager may have extremely different responsibilities and authority depending upon the size of the hospital and the ownership or administrator’s delegation. Practice managers will have knowledge of all the responsibilities of a veterinary office manager and have the ability to further the management of a veterinary hospital by having direct authority and decision-making responsibilities over all business aspects of the veterinary practice.
The statement is - False.
In the pre-industrial societies, the economy was far from being based on providing information and services. The economy was largely based on two things, agriculture and trade.
The agriculture was the basis and the dominant sector in the pre-industrial economy. The more agricultural products a nation had, the more it had to trade, thus becoming wealthy. This can easily be seen in the colonies that the European countries had in the pre-industrial period, where every inch of the land that was suitable for agriculture was used, and latter those products were shipped and traded in order to become wealthier.
It’s b you better pick b because it’s b
The time it takes for 1g of strontium-90 to decay to 250 mg is; 57.6 years
<h3>What is the half life of an element?</h3>
The formula for half life is;
A(t) = A₀ * (¹/₂)^(t/t_1/2)
Where;
A(t) is amount left after t years
A₀ the initial quantity of the substance that will undergo decay;
t_1/2 is the half-life of the decaying quantity.
We are given;
t_1/2 = 28.8 years
A₀ = 1 g
A(t) = 250 mg = 0.25 g
Thus;
0.25 = 1 * (¹/₂)^(t/28.8)
log 0.25 = (t/28.8) log (1/2)
-0.60206 = (t/28.8) * -0.3010
t = 2 * 28.8
t = 57.6 years
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