F(X) = 6/X
F(X) = 6 • 1/X
F(X) = 6 • x^-1
F(X) = 6x^-1
F'(X) = 6 • d(x^-1)/dx
F'(X) = 6 • -1x^-1-1
F'(X) = 6 • -1x^-2
F'(X) = -6x^-2
F'(X) = -6/x^2
F'(-2) = -6/(-2)^2
F'(-2) = -6/4
F'(-2) = -3/2
The solution would be C. -3/2.
Answer:
its 11
Step-by-step explanation:
sorry. i feel so bad
It becomes a liquid
hope this helped
For this case we have that by definition, the point-slope equation of a line is given by:
Where:
m: It's the slope
b: It is the cut-off point with the y axis
We have two points:
We found the slope:
Thus, the equation is of the form:
We substitute one of the points and find "b":
Finally, the equation is:
Answer:
Answer:
Step-by-step explanation:
In going from (5, 5) to (10, 8), x (the run) increases by 5 and y (the rise) increases by 3. Thus, the slope of the line connecting the first two points is m = 3/5.
In going from (1, 13) to (4, 8), x (the run) increases by 3 and y (the rise) decreases by 5. Thus, the slope of the line connecting the first two points is m = -5/3
Because these results are negative reciprocals of one another, the two lines are PERPENDICULAR to one another.
