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Maru [420]
3 years ago
13

What is the mass of a 15 cm^3 piece of iron if the density of iron is 7.87G/ML

Chemistry
1 answer:
Effectus [21]3 years ago
6 0

Answer:

118.05 grams

Explanation:

mL = cm³

Density = mass/volume

Let x = mass

Our equation will look like this: x/15 = 7.87

Multiply both sides by 15 to isolate the variable, x

15(x/15) = 15(7.87)

15x/15 = 118.05

x = 118.05

You might be interested in
What is the rate law for the reaction 2A + 2B + 2C --> products
-Dominant- [34]

Answer:

R = 47.19 [A]*([B]^2)*[C]

Explanation:

The rate law for the reaction 2A + 2B + 2C --> products

Is being sought.

The reaction rate R could be expressed as  

R = k ([A]^m)*([B]^n)*([C]^p)                      (1)

where m, n, and p are the reaction orders with respect to (w.r.t.) components A, B and C respectively. This could be reduced to

R = ka ([A]^m)                   (2)

Where ka=(k[B]^n)*([C]^p);    

R = kb ([B]^n)                    (3)

Where kb=(k[A]^m)*([C]^p); and  

R = kc ([C]^p)                     (4)

Where kc=(k[A]^m)*([B]^n).

Equations (2), (3) and (4) are obtained for cases when the concentrations of two components are kept constant, while only one component’s concentration is varied. We can determine the reaction wrt each component by employing these equations.  

The readability is very much enhanced when the given data is presented in the following manner:

Initial [A]  0.273   0.819   0.273   0.273

Initial [B]  0.763   0.763   1.526   0.763

Initial [C]  0.400   0.400    0.400   0.800

Rate           3.0       9.0       12.0       6.0

Run#  1  2 3  4

Additional row is added to indicate the run # for each experiment for easy reference.

First, we use the initial rate method to evaluate the reaction order w.r.t. each component [A], [B] and [C] based on the equations (2), (3) and (4) above.

Let us start with the order wrt [A]. From the given data, for experimental runs 1 and 2, the concentrations of reactants B and C were kept constant.

Increasing [A] from 0.273 to 0.819 lead to the change of R from 3.0 to 9.0, hence we can apply the relation based on equation (2) between the final rate R2, the initial rate R1 and the final concentration [A2] and the initial concentration [A1] as follows:

R2/R1=ka[A2]^m/ka[A1]^m=([A2]/[A1])^m

9.0/3.0 = (0.819/0.273)^m

3 = (3)^m = 3^1  -> m = 1

Similarly, applying experimental runs 1 and 3 could be applied for the determination of n, by employing equation (3):  

R3/R1=kb[B3]^n/kb[B1]^n=([B3]/[B1])^n

12/3= (1.526/0.763)^n

4= 2^n, -> n = 2

And finally for the determination of p we have using runs 4 and 1:

R4/R1=kc[C4]^p/kc[C1]^p=([C4]/[C1])^p

6/3= (0.8/0.4)^p

2= 2^p , -> p = 1

Therefore, plugging in the values of m, n and p into equation (1), the rate law for the reaction will be:

R = k [A]*([B]^2)*[C]

The value of the rate constant k could be estimated by making it the subject of the formula, and inserting the given values, say in run 1:

k = R /( [A]*([B]^2)*[C]) = 3/0.273*(0.763^2)*0.4 =

47.19

Finally, the rate law is

R = 47.19 [A]*([B]^2)*[C]

7 0
4 years ago
An element's atomic mass does not include the mass of its _____.
Oksi-84 [34.3K]

。☆✼★ ━━━━━━━━━━━━━━  ☾

The correct option would be 'electrons'

This is because electrons have a relative mass of zero.

Have A Nice Day ❤

Stay Brainly! ヅ

- Ally ✧

。☆✼★ ━━━━━━━━━━━━━━  ☾

3 0
3 years ago
Glucose C6 H12 O6 is the simple sugar that plants make what is the total number of atoms in glucose
12345 [234]

Answer:

Total number of atoms in glucose are 24.

Explanation:

Photosynthesis:

It is the process in which in the presence of sun light and chlorophyll by using carbon dioxide and water plants produce the oxygen and glucose.

Carbon dioxide + water + energy →   glucose + oxygen

water is supplied through the roots, carbon dioxide collected through stomata and sun light is capture  by chloroplast.

Chemical equation:

6H₂O + 6CO₂ + energy  →   C₆H₁₂O₆ + 6O₂

Glucose molecule =  C₆H₁₂O₆

Total number of atoms = 6+12+6 = 24

Types of atoms = 3 (C,H,O)

3 0
4 years ago
Three isotopes of oxygen are oxygen-16 oxygen-17 and oxygen-18. Write the symbol for each, including the atomic number and mass
Karo-lina-s [1.5K]
The symbol of an isotope is:
^A _Z X
A - the mass number
Z - the atomic number
X - the symbol of an element

The symbol of oxygen is O.

The atomic number is the same for all isotopes of one element. For oxygen it's 8, because every atom of oxygen has 8 protons in its nucleus.

The mass number is the number of nucleons (protons + neutrons) in the nucleus of an atom, and it's given in the name of an isotope. Oxygen-16 has the mass number 16, oxygen-17 has the mass number 17, oxygen-18 has the mass number 18.

Oxygen-16: ^{16} _8 O

Oxygen-17: ^{17} _8 O

Oxygen-18: ^{18} _8 O
5 0
3 years ago
Why do solutions containing acids conduct an electric current?
Marizza181 [45]
The answers to this problem is C
7 0
3 years ago
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