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8_murik_8 [283]
3 years ago
14

All matter has: volume mass density all of the above

Chemistry
2 answers:
rewona [7]3 years ago
4 0
I think the answer is mass.
Crank3 years ago
3 0

Answer:

All matter has mass

Explanation:

Have a great day!

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Mountain Gorilla’s are more vulnerable to extinction because they are endangered due to habitat loss, diseases, poaching, ect.
6 0
3 years ago
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Calculate the number of calories needed to increase the temperature of 50.0 g of copper metal from 21.0 degrees C to 75.0 degree
KonstantinChe [14]
<h3>Answer:</h3>

1031.4 Calories.

<h3>Explanation:</h3>

We are given;

Mass of the copper metal = 50.0 g

Initial temperature = 21.0 °C

Final temperature, = 75°C

Change in temperature = 54°C

Specific heat capacity of copper = 0.382 Cal/g°C

We are required to calculate the amount of heat in calories required to raise the temperature of the copper metal;

Quantity of heat is given by the formula,

Q = Mass × specific heat capacity × change in temperature

   = 50.0 g × 0.382 Cal/g°C × 54 °C

   = 1031.4 Calories

Thus, the amount of heat energy required is 1031.4 Calories.

4 0
3 years ago
The relationship between moles and volume, when pressure and temperature of a gas are held constant, is: V/n =
Dvinal [7]

Answer:

If the moles of gas are tripled, the volume must also triple.

Explanation:

According to Avogadro law,

Equal volume of all the gases at same temperature and pressure have equal number of molecules.

The number of moles and volume are directly related to each other. By increasing the number of moles volume also goes to increase with same ratio.

When number of moles decreases the volume also goes to decrease at constant temperature and pressure.

Mathematical expression:

V ∝ n

V = Kn

V/n = k

When volume is changed from V₁ to V₂ by changing the number of moles from n₁ to n₂. Then expression will be,

V₁/n₁ = V₂/n₂

5 0
3 years ago
Calculate the Standard Enthalpy of the reaction below:
Norma-Jean [14]

Answer:

(we use hess's law) it is so simple but the second reaction is not correct please right it

6 0
3 years ago
4
STALIN [3.7K]

Answer: The space occupied by the gas at 400 torr and 25^{o}C is 250 mL.

Explanation:

Given: V_{1} = 250 mL,    P_{1} = 800 torr,     T_{1} = 50^{o}C

V_{2} = ?,         P_{2} = 400 torr,        T_{2} = 25^{o}C

Formula used is as follows.

\frac{P_{1}V_{1}}{T_{1}} = \frac{P_{2}V_{2}}{T_{2}}

Substitute the values into above formula as follows.

\frac{P_{1}V_{1}}{T_{1}} = \frac{P_{2}V_{2}}{T_{2}}\\\frac{800 torr \times 250 mL}{50^{o}C} = \frac{400 torr \times V_{2}}{25^{o}C}\\V_{2} = 250 mL

Thus, we can conclude that space occupied by the gas at 400 torr and 25^{o}C is 250 mL.

7 0
3 years ago
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