Answer:
how far down stream will the concentration be reduced by from 10 mg/L to 1 mg/L? = 108meters
Explanation:
check the file below for further explanation
This is true, i double checked!!
.513mol x (102g/1mol)
Essentially, this is .513 x 102
Which equals: 52.326
But because you can only have 3 significant figures, your answer is:
52.3 grams
I hope this Helps!
The value of x : 2
<h3>Further explanation</h3>
Semi-normal Hydrochloric acid solution = 0.5 N = 0.5 M
for titration :
M₁V₁n₁=M₂V₂n₂(1=HCl,2=Na₂CO₃)
![\tt 0.5\times 20\times 1=M_2\times V_2\times 2\\\\M_2V_2=5~mlmol=5.10^{-3}mol](https://tex.z-dn.net/?f=%5Ctt%200.5%5Ctimes%2020%5Ctimes%201%3DM_2%5Ctimes%20V_2%5Ctimes%202%5C%5C%5C%5CM_2V_2%3D5~mlmol%3D5.10%5E%7B-3%7Dmol)
![\tt MW=\dfrac{mass}{mol}=\dfrac{0.715}{5.10^{-3}}=143~g/mol](https://tex.z-dn.net/?f=%5Ctt%20MW%3D%5Cdfrac%7Bmass%7D%7Bmol%7D%3D%5Cdfrac%7B0.715%7D%7B5.10%5E%7B-3%7D%7D%3D143~g%2Fmol)
MW Na₂CO₃.xH₂O=143
MW Na₂CO₃.xH₂O = MW Na₂CO₃+ MW xH₂O = 143
MW Na₂CO₃ = 106 g/mol
MW xH₂O = 18x
Equation :
![\tt 106+18x=143\\\\18x=37\\\\x=\dfrac{37}{18}=2.056\approx 2](https://tex.z-dn.net/?f=%5Ctt%20106%2B18x%3D143%5C%5C%5C%5C18x%3D37%5C%5C%5C%5Cx%3D%5Cdfrac%7B37%7D%7B18%7D%3D2.056%5Capprox%202)