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prisoha [69]
3 years ago
15

Why do you think large differences in temperature between the wet bulb and dry bulb thermometers are possible only at higher tem

peratures?
Chemistry
1 answer:
olganol [36]3 years ago
7 0

Answer:

This is the temperature indicated by a moistened thermometer bulb exposed to the air flow. The evaporation is reduced when the air contains more water vapor. The wet bulb temperature is always lower than the dry bulb temperature but will be identical with 100% relative humidity.

Explanation:

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Which part of the atom forms chemical bonds?
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Out of the choices given, the part of the atom that forms chemical bonds are the outermost electrons. The correct answer is B. 
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You do an experiment in which you need 0.25 mole of tyrosine (C,H11 NO3).
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Answer:

B.90.5 g

Explanation:

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3 years ago
3. Balance each of the following redox reactions in the listed aqueous environment. (4 pts each, 8 pts total) Crs)NO3 (a) Cr (a)
GrogVix [38]

Explanation:

(a)   The given reaction equation is as follows.

        Cr(s) + NO^{-}_{3}(aq) \rightarrow Cr^{3+}(aq) + NO(g) (acidic)

So, here the reduction and oxidation-half reactions will be as follows.

Oxidation-half reaction: Cr(s) \rightarrow Cr^{3+}(aq) + 3e^{-}

Reduction-half-reaction: NO^{-}_{3} + 3e^{-}(aq) \rightarrow NO(g)

As total charge present on reactant side is -1 and total charge present on product side is +3. And, since it is present in aqueous medium. Hence, we will balance the charge for this reaction equation as follows.

      Cr(s) + NO^{-}_{3}(aq) + 4H^{+}(aq) \rightarrow Cr^{3+}(aq) + NO(g) + 2H_{2}O(l) (acidic)

(b)   The given reaction equation is as follows.

        HCO^{-}_{3}(aq) + Ag(s) + NH_{3}(aq) \rightarrow H_{2}CO(aq) + Ag(NH_{3})^{+}_{2}(aq) (basic)

So, here the reduction and oxidation-half reactions will be as follows.

Reduction-half reaction: HCO^{-}_{3}(aq) + 4e^{-} \rightarrow H_{2}CO(aq)

Oxidation-half reaction: Ag(s) \rightarrow Ag(NH_{3})^{+}_{2}(aq) + 1e^{-}

Hence, to balance the number of electrons in this equation we multiply it by 4 as follows.

      4Ag(s) \rightarrow 4Ag(NH_{3})^{+}_{2}(aq) + 4e^{-}

Therefore, balancing the whole reaction equation in the basic medium as follows.

      H_{2}CO(aq) + 4Ag(NH_{3})^{+}_{2}(aq) + 5OH^{-}(aq) \rightarrow HCO^{-}_{3}(aq) + 4Ag(s) + 8NH_{3}(aq) + 3H_{2}O(l)

6 0
3 years ago
What is the molecular formula of Ferric Oxide with criss-cross method ​
Ksenya-84 [330]

Answer: Fe2O3

Explanation: By applying crisscross method, the formula will be Fe2O3.

6 0
2 years ago
Is pellet of sodium is cut into two parts physical or chemical change?​
Klio2033 [76]

Answer:

physical change

Explanation:

the cutting doesnt change the chemical structure of the sodium

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