Answer:
A. He sent a cathode ray between electrically charged metal plates
Answer:
(dont know if this is correct took this last year)
Explanation:
1 hydrogen atom plus 1 chlorine atom is equal to 2 hydrochloric acids due to the fact that there are 2 atoms in both substances and the equation has to stay constant throughout according to the law of conservation of mass
same goes for 2 sulfate atoms and 3 oxygen atoms
in order to balance this this the sulfate atoms have to take into account that their are 2 sulfate atoms and 6 oxygen atoms so you have to add more sulfates to make them both equal 6 then balance it with the oxygens
When Na3po4 dissolves in water to produce an electrolytic solution. The osmolarity of a 2. 0 × 10-3 m Na3po4 solution is 0.008osmol/L.
Osmolarity is defined as the number of osmoles of solute particles per unit volume of the solution.
In other words osmolarity is the multiple if molarity
Osmolarity = i× molarity
Here i represents the van't Hoff factor,
⇒ 
3 Moles of 
+ 1 mole 
= 4
The number of moles of particles of solute produced in solution are actually called osmoles.
As a result, the van't Hoff factor will be equal to
i=4 Moles ions produced (osmoles) 1mole 
.dissolved =4
Since we know that,
= 
Osmolarity =
= 
Thus, the Osmolarity of given solution is 0.008 osmol/L.
learn more about Osmolarity:
brainly.com/question/13597129
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You did not include the options but I can tell you the product ratio.
The product ratio is the mole ratio of the products of the reaction.
From the balanced chemical equation you have all the mole ratios:
The given equation is: 2 C6H5COOH + 15O2 --> 14 CO2 + 6H2O
The mole ratios are: 2 C6H5COOH: 15 O2: 14 CO2 : 6 H2O
The products are CO2 and H2O
Their mole ratio = 14 CO2 : 6 H2O
That can be expressed as:
14 mol CO2 7 mol CO2
----------------- = -----------------
6 mol H2O 3 mol H2O
It is also the same that:
6 mol H2O : 14 mol CO2
6 mol H2O 3 mol H2O
------------------ = -------------------
14 mol CO2 7 mol CO2
So, compare your options to the ratios show above and pick the proper ratio.
