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pychu [463]
2 years ago
14

Balance NaOH + H3PO4->H2O + Na3PO4

Chemistry
1 answer:
Masteriza [31]2 years ago
7 0

Answer:

3NaOH + H3PO4 ---> 3H2O + Na3PO4

Explanation:

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What is the concentration of OH − and pOH in a 0.00066 M solution of Ba ( OH ) 2 at 25 ∘ C? Assume complete dissociation.
Allushta [10]

<u>Answer:</u> The hydroxide ion concentration and pOH of the solution is 1.32\times 10^{-3}M  and 2.88 respectively

<u>Explanation:</u>

We are given:

Concentration of barium hydroxide = 0.00066 M

The chemical equation for the dissociation of barium hydroxide follows:

Ba(OH)_2\rightarrow Ba^{2+}+2OH^-

1 mole of barium hydroxide produces 1 mole of barium ions and 2 moles of hydroxide ions

pOH is defined as the negative logarithm of hydroxide ion concentration present in the solution

To calculate pOH of the solution, we use the equation:

pOH=-\log[OH^-]

We are given:

[OH^-]=(2\times 0.00066)=1.32\times 10^{-3}M

Putting values in above equation, we get:

pOH=-\log(1.32\times 10^{-3})\\\\pOH=2.88

Hence, the hydroxide ion concentration and pOH of the solution is 1.32\times 10^{-3}M  and 2.88 respectively

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Which combination of reactants would result in a neutralization reaction with sodium nitrate,
Debora [2.8K]

Answer:

(B) HNO3 + NaOH

Explanation:

Hello,

In this case, for the production of sodium nitrate a substance having the sodium as a cation should react with another substance having the nitrate anion. Moreover, neutralization reactions are carried out when bases react with acids, such is the case of nitric acid and sodium hydroxide:

NaOH+HNO_3\rightarrow NaNO_3+H_2O

Thus, the answer is (B) HNO3 + NaOH  as the other options involve salts rather than acids or bases as starting reactants.

Regards.

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