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Basile [38]
3 years ago
14

A teaspoon of salt is dissolved in a cup of water. What does the salt represent in this example?

Chemistry
2 answers:
lina2011 [118]3 years ago
6 0
The salt is the Solute.Think of the solute as the lesser one added to the other to be dissolved.
adell [148]3 years ago
3 0
The salt is the solute
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Explain how an ionic compound forms from these elements.
grin007 [14]

Ionic compounds are formed by the complete transfer of electrons from more electronegative elements to less electronegative elements.

7. <u>Sodium Nitride (Na₃N)</u> is an ionic substance.

8. The ionic formula for <u>Lithium Oxide is Li₂O</u>

9. The <u>compound SrF₂</u>

10. Aluminum Sulfide is a chemical compound with the <u>formula Al₂S₃.</u>

An ionic compound is a chemical compound composed of ions held together via electrostatic forces termed ionic bonding. The compound is neutral standard but includes definitely charged ions known as cations and negatively charged ions known as anions.

An ionic compound is a chemical compound composed of ions held collectively by means of electrostatic forces termed ionic bonding. The compound is neutral normal however consists of positively charged ions known as cations and negatively charged ions referred to as anions. Ionic compounds incorporate ions and are held collectively via the attractive forces of most of the oppositely charged ions.

Learn more about ionic compounds here:-

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8 0
1 year ago
Balancing nuclear equations is slightly different than balancing chemical equations. The major difference is that in nuclear rea
vesna_86 [32]

Answer:

The correct answer is - 4.

Explanation:

As we known and also given that the total of the superscripts that is mass numbers, A in the reactants and products must be the same.The mass of products A can understand and calculated by this -

The sum of the product mass number of products = mass of reactant

237Np93 →233 Pa91 +AZX is the equation,

Solution:

Mass of reactants = 237

Mass of products are - Pa =233 and A = ?

233 + A = 237

A = 237 - 233

A = 4

So the equation will be:

237Np93 →233 Pa91 +4He2 (atomic number Z = 2 ∵ difference in the atomic number of reactant and products)

5 0
3 years ago
Almost all of the energy on the surface of earth come from what
Rashid [163]
The sun solar energy produce all the energy
7 0
3 years ago
Read 2 more answers
Write the formula for potassium oxide. why do you not need prefixes in the name ​
Molodets [167]

Potassium oxide: K₂O.

There's no need for prefixes since K₂O is an ionic compound.

<h3>Explanation</h3>

Find the two elements on a periodic table:

  • Potassium- K- on the left end of period four.
  • Oxygen- O- near the right end of periodic two.

Elements on the bottom-left corner of the periodic table are metals. Those on the top-right corner are nonmetals.

  • Potassium is a metal,
  • Oxygen is a nonmetal.

A metal and a nonmetal combine to form an ionic compound. Potassium oxide is likely to be an ionic compound. It contains two types of ions:

  • Potassium ions: Potassium is group 1 of the periodic table. It is an alkaline metal. Like other alkaline metals such as sodium Na, potassium K tends to lose one electron and form ions of charge +1 in compounds. The ion would be K⁺.
  • Oxide ions from oxygen: Oxygen is the second most electronegative element on the periodic table. It tends to gain two electrons and form the oxide ion \text{O}^{2-} when it combines with metals.

The two types of ions carry opposite charges. They shall pair up at a certain ratio such that they balance the charge on each other. The charge on each \text{O}^{2-} ion is twice that on a \text{K}^{+} ion. Each \text{K}^{+} would pair up with two \text{O}^{2-}. Hence the subscript in the formula: \text{K}_{\bf 2}\text{O}.

There are two classes of compounds:

  • Covalent compounds, which need prefixes, and
  • Ionic compounds, which need no prefix.

Prefixes are needed only in covalent compounds. For instance in the covalent compound carbon dioxide \text{CO}_2, the prefix di- indicates that there are two oxygen atoms in the formula \text{CO}_2. However, there's no need for prefix in ionic compounds such as \text{K}_2\text{O}.

7 0
3 years ago
In one experiment, the reaction of 1.00 mercury and an excess of sulfur yielded 1.16g of a sulfide of mercury
Nuetrik [128]

<u>Answer and Explanation:</u>

Mercury combines with sulfur as follows -

Hg + S = HgS

Hg = 200,59

S = 32,066 Therefore 1.58 g of Hg will react with -

1.58 multiply with 32,066 divide by 200,96 of sulfur.

= 0.25211 g S

This will form 1.58 + 0.25211 g HgS  = 1.83211 g HgS

The amount of S remaining = 1.10 - 0.25211  = 0.84789 g

5 0
3 years ago
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