Calcium Chloride's chemical formula is CaCl2.
<span>In a cup of salt water, the solvent is water and the solute is the salt. When the two mixed they form a solution. The solvent is what dissolves the solute. It has the largest composition in a solution. The solute has a smaller composition in a solution and it is usually in solid form.</span>
Answer : If any atom has more electrons than one energy level can hold, then automatically the electron is accommodated in the next energy level (shell). The remaining extra electrons starts to fill the next energy level. This produces the valency of that particular atom.
Answer :
(A) The number of moles of
ions per liter is, 0.1 moles/L
(B) The number of molecules of
ion is, ![6.022\times 10^{10}](https://tex.z-dn.net/?f=6.022%5Ctimes%2010%5E%7B10%7D)
(C) The pH of the solution will be, 4
<u>Solution for part A :</u>
First we have to calculate the pOH of the solution.
As we know that,
![pH+pOH=14\\\\13+pOH=14\\\\pOH=1](https://tex.z-dn.net/?f=pH%2BpOH%3D14%5C%5C%5C%5C13%2BpOH%3D14%5C%5C%5C%5CpOH%3D1)
Now we have to calculate the moles of
ion per liter.
![pOH=-\log [OH^-]\\\\1=-\log [OH^-]](https://tex.z-dn.net/?f=pOH%3D-%5Clog%20%5BOH%5E-%5D%5C%5C%5C%5C1%3D-%5Clog%20%5BOH%5E-%5D)
![[OH^-]=0.1moles/L](https://tex.z-dn.net/?f=%5BOH%5E-%5D%3D0.1moles%2FL)
<u>Solution for part B :</u>
First we have to calculate the
ion concentration.
![pH=-\log [H^+]\\\\13=-\log [H^+]](https://tex.z-dn.net/?f=pH%3D-%5Clog%20%5BH%5E%2B%5D%5C%5C%5C%5C13%3D-%5Clog%20%5BH%5E%2B%5D)
![[H^+]=10^{-13}moles/L](https://tex.z-dn.net/?f=%5BH%5E%2B%5D%3D10%5E%7B-13%7Dmoles%2FL)
Now we have to calculate the number of molecules of
ion
As, 1 mole contains
number of molecules of
ion
So,
moles contains
number of molecules of
ion
<u>Solution for part C :</u>
![pH=-\log [H^+]\\\\pH=-\log (1\times 10^{-4})](https://tex.z-dn.net/?f=pH%3D-%5Clog%20%5BH%5E%2B%5D%5C%5C%5C%5CpH%3D-%5Clog%20%281%5Ctimes%2010%5E%7B-4%7D%29)
![pH=4](https://tex.z-dn.net/?f=pH%3D4)