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DENIUS [597]
3 years ago
13

22. Use the information from Question 21. Show how the Distributive Property can be used to find the area of Marlene's living ro

om.
23 Use the algebraic expression for length and width of Marlene's living room found in the diagram and the value of x found in Question 21C

A.find the actual length and width of her living room.

B. Find the actual area of Marlene's living room use actual dimensions.

Mathematics
2 answers:
Eva8 [605]3 years ago
3 0

Answer:

420 feet

Step-by-step explanation:

x=14, so you plug in 14 for x*(x+2)

Elza [17]3 years ago
3 0
Question 22 x (2x+2) = 2x^2 +2x
Question 23 value of x = 18/5
The actual length and width of living room is : length 3 3/5 , width 11 1/5
B: the actual dimensions of living room is : 40 8/25
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An electrician charges $15 for a service call plus $25 per hour. The total bill for a recent job was $165.
Aleksandr-060686 [28]

Answer:

h = 6

Step-by-step explanation:

Equation:

15 + 25h = 165

Subtract 15 from both sides

25h = 150

Divide both sides by 25

h = 6

So 6 hours

Hope this helped :)

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3 0
3 years ago
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Which of the following is a polynomial?
Rom4ik [11]

Answer:

A. 3x^2+6x is a polynomial

8 0
3 years ago
Carla is baking brownies for the school bake sale. The batter fills a pan that is 20 cm long by 16 cm wide by 4.4 cm deep.Then,
barxatty [35]

The volume of the first pan is (length x width x depth) =

                                               (20cm x 16cm x 4.4cm) = 1408 cm³ .

The batter fills it, so we know there is 1408 cm³ of batter.

Somehow, Carla manages to transfer every drop and smidgen of batter to
the new pan, leaving not a single drip of it in the first pan.  So we know that
there is 1408 cm³ of batter in the new pan.  It will spread out to fill the whole
length and width of the new pan, and we're to calculate how deep it will be.

                         (length x width x depth)  =  1408 cm³

                       (20cm x 20cm) x (depth)  =  1408 cm³

                                (400 cm²) x (depth)  =  1408 cm³

Divide each side by  400cm² :      depth  =  1408 cm³ / 400cm²

                                                               =  3.52 cm

Since the new pan is 5 cm deep, this works.  The batter doesn't
overfill it and glurb out over the top and all over the counter.

The question asked how far the batter is <em>from the top of the pan</em>.

The pan is        5 cm deep.
The batter is 3.52cm deep.

The batter comes up to (5 - 3.52) = 1.48 cm from the top of the pan.

Rounded to the nearest tenth of a cm, that's  <em>1.5 cm  </em>from the top.

5 0
3 years ago
Deion loves to play the piano but doesn't like practicing the exercises his piano teacher
lianna [129]
Ok so Deion practices the piano, right, but now we’re talking about cookies? WDYM by COOKIES?
8 0
3 years ago
In a simple random sample of 300 boards from this shipment, 12 fall outside these specifications. Calculate the lower confidence
Lyrx [107]

Answer:

The 95% confidence interval for the percentage of all boards in this shipment that fall outside the specification is (1.8%, 6.2%).

Step-by-step explanation:

In a random sample of 300 boards the number of boards that fall outside the specification is 12.

Compute the sample proportion of boards that fall outside the specification in this sample as follows:

\hat p =\frac{12}{300}=0.04

The (1 - <em>α</em>)% confidence interval for population proportion <em>p</em> is:

CI=\hat p\pm z_{\alpha/2}\sqrt{\frac{\hat p(1-\hat p)}{n}}

The critical value of <em>z</em> for 95% confidence level is,

z_{\alpha/2}=z_{0.05/2}=z_{0.025}=1.96

*Use a <em>z</em>-table.

Compute the 95% confidence interval for the proportion of all boards in this shipment that fall outside the specification as follows:

CI=\hat p\pm z_{\alpha/2}\sqrt{\frac{\hat p(1-\hat p)}{n}}\\=0.04\pm1.96\sqrt{\frac{0.04(1-0.04)}{300}}\\=0.04\pm0.022\\=(0.018, 0.062)\\\approx(1.8\%, 6.2\%)

Thus, the 95% confidence interval for the proportion of all boards in this shipment that fall outside the specification is (1.8%, 6.2%).

6 0
3 years ago
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