Answer:
=18.5°C
Explanation:
Heat lost by steam=heat gained by ice.
ΔH(ice)=ΔH(steam)
ΔH=MC∅ where M is the mass of the substance, C is the specific heat capacity and ∅ is the temperature change of the substance.
Let final temperature be y°C
Then ΔH for ice=MLf+MC(y-0)°C
ΔH for steam= Mlv+MC(100-y)°C
(25kg×3.34×10⁵J/kg)+25kg×4180J/kgK×y°C= 4kg×2.23×10⁶J/kg+4kg×4180J/kgK×(100-y)
8350000J +104500y =8920000J+1672000J-16720y
Collect like terms together.
104500y+16720y=8920000J+1672000J-8350000J
121220y=2242000
y=18.5K
Final temperature= 0°C +18.5°C
=18.5°C