Answer:
OBr₂
Explanation:
<em>The ionic character depends on the difference of electronegativity between the elements. The higher ΔEN, the greater the ionic character.</em>
SBr₂
ΔEN = |EN(S)-EN(Br)| = |2.5-2.8| = 0.3
OBr₂
ΔEN = |EN(O)-EN(Br)| = |3.5-2.8| = 0.7
SeCl₂
ΔEN = |EN(Se)-EN(Cl)| = |2.4-3.0| = 0.6
TeI₂
ΔEN = |EN(Te)-EN(I)| = |2.1-2.5| = 0.4
SCl₂
ΔEN = |EN(S)-EN(Cl)| = |2.5-3.0| = 0.5
OBr₂ is the molecule with the most ionic character.
Answer ;
As an inert gas is nonreactive and thus, it won't affect the equilibrium
Answer:
The percentage of germanium in germatite is 6.0003%.
Explanation:
Mass of an ore of germanite = 1.00 grams
Mass of germanium chloride = 0.177 grams
Percentage of germanium in germanium chloride = 33.9%
Let the mass of germanium present in germanium chloride be x.
Percentage of an element in a compound:
x = 0.060003 grams
Percentage of germanium in an ore of germanite:
The percentage of germanium in germatite is 6.0003%.
Cofactors:
A. Coenzyme A (CoA-SH)
B. NAD+
C. Thiamine pyrophosphate (TPP)
D. FAD
E. Lipoic acid in oxidized form
Roles:
E... Attacks and attaches to the central carbon in pyruvate.
A...Oxidizes FADH2.
C...Accepts the acetyl group from reduced lipoic acid.
D... Oxidizes the reduced form of lipoic acid.
B... Initial electron acceptor in oxidation of pyruvate.
Answer: 1.77 kg of manganese (IV) oxide reacts to produce 1.12kg of manganese metal.
Explanation:
The balanced chemical equation is:
To calculate the moles, we use the equation:
moles of manganese =
According to stoichiometry :
3 moles of is produced by = 3 moles of
Thus 20.4 moles of is produced by = of
Mass of (1kg=1000g)
Thus 1.77 kg of manganese (IV) oxide reacts to produce 1.12kg of manganese metal.