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Agata [3.3K]
2 years ago
11

Group 1 elements have an average electronegativity of 0.84 (not including hydrogen). Group 17 elements have an average electrone

gativity of 2.99. These two groups often form bonds. Given this information, which kind of bond will they likely form (ionic or covalent), and what evidence supports your claim? If it is ionic, then include which group gives up its electron to the other group. In three to five sentences, explain your reasoning
Chemistry
1 answer:
Ksenya-84 [330]2 years ago
3 0

The elements of group 1 makes ionic bond with the elements of group 7 due to high difference of electronegativity values.

<h3>Type of bond between group 1 and 7</h3>

The elements of first group lose its one outermost electrons while on the other hand, the elements of seven group needs one electron so they gain that one electron so they make an ionic bond with each other.

So we can conclude that the elements of group 1 makes ionic bond with the elements of group 7 because of the high difference of electronegativity values.

Learn more about electronegativity here: brainly.com/question/2415812

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How many moles of sodium hydroxide would react with 1 Mole of sulphuric acid?
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Answer:

Two moles.

Explanation:

Sulphuric (sulfuric) acid \rm H_2SO_4 is a diprotic acid. When one mole of \rm H_2SO_4 molecules dissolve in water, two moles of \rm H^{+} ions would be produced.

\rm H_2SO_4 \to 2\, H^{+} + {SO_4}^{2-}.

On the other hand, sodium hydroxide \rm NaOH is a monoprotic base. When one mole of \rm NaOH formula units dissolve in water, only one mole of hydroxide ions \rm OH^{-} would be produced.

\rm NaOH \to Na^{+} + OH^{-}.

Note that \rm H^{+} and \rm OH^{-} react at a one-to-one ratio:

\rm H^{+} + OH^{-} \to H_2O.

As a result, it would take 2\; \rm mol of \rm OH^{-} to react with the \rm 2\; mol of \rm H^{+} that was released when 1\; \rm mol of \rm H_2SO_4 is dissolved in water. Since one mole of \rm NaOH formula units could produce only one mole of \rm OH^{-}, it would take \rm 2\; mol of \rm NaOH formula units to produce that 2\; \rm mol of \rm OH^{-} for reacting with 1\; \rm mol of \rm H_2SO_4.

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3 years ago
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How many moles are in 25 g KMnO4
Ronch [10]

Answer:

0.158 moles KMnO4

Explanation:

According to the Periodic Table,

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O = 16.00 g/mol

KMnO4 = 39.10 g/mol + 54.94 g/mol + 4(16.00 g/mol) = 158.04 g/mol

25.0 grams KMnO4              1 mole

-----------------------------  x --------------------------  = 0.158 moles KMnO4

                                          158.04 grams

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