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Agata [3.3K]
2 years ago
11

Group 1 elements have an average electronegativity of 0.84 (not including hydrogen). Group 17 elements have an average electrone

gativity of 2.99. These two groups often form bonds. Given this information, which kind of bond will they likely form (ionic or covalent), and what evidence supports your claim? If it is ionic, then include which group gives up its electron to the other group. In three to five sentences, explain your reasoning
Chemistry
1 answer:
Ksenya-84 [330]2 years ago
3 0

The elements of group 1 makes ionic bond with the elements of group 7 due to high difference of electronegativity values.

<h3>Type of bond between group 1 and 7</h3>

The elements of first group lose its one outermost electrons while on the other hand, the elements of seven group needs one electron so they gain that one electron so they make an ionic bond with each other.

So we can conclude that the elements of group 1 makes ionic bond with the elements of group 7 because of the high difference of electronegativity values.

Learn more about electronegativity here: brainly.com/question/2415812

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The mass of an atom of element x is equivalent to the total mass of 7 hydrogen atoms.
Agata [3.3K]

Answer:

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Explanation:

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2 years ago
Calculate either [ H 3 O + ] or [ OH − ] for each of the solutions.
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Answer: Solution A : [H_3O^+]=0.300\times 10^{-7}M

Solution B : [OH^-]=0.107\times 10^{-5}M

Solution C : [OH^-]=0.177\times 10^{-10}M

Explanation:

pH or pOH is the measure of acidity or alkalinity of a solution.

pH is calculated by taking negative logarithm of hydrogen ion concentration and pOH is calculated by taking negative logarithm of hydroxide ion concentration.

pH=-\log[H_3O^+]

pOH=-log[OH^-}

pH+pOH=14

[H_3O^+][OH^-]=10^{-14}

a. Solution A: [OH^-]=3.33\times 10^{-7}M

[H_3O^+]=\frac{10^{-14}}{3.33\times 10^{-7}}=0.300\times 10^{-7}M

b. Solution B : [H_3O^+]=9.33\times 10^{-9}M

[OH^-]=\frac{10^{-14}}{9.33\times 10^{-9}}=0.107\times 10^{-5}M

c. Solution C : [H_3O^+]=5.65\times 10^{-4}M

[OH^-]=\frac{10^{-14}}{5.65\times 10^{-4}}=0.177\times 10^{-10}M

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2 years ago
Which atom would be expected to have a half-filled 6s subshell
eduard

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Explanation:

A half-filled 6s subshell would be 6s^1

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