Mr. Nesbit realized that the bell was about to ring and he was going to be late. So

A company that produces fine crystal knows from experience that 13% of its goblets have cosmetic flaws and must be classified as

Kisachek [45]

Answer:

(a) The probability that only one goblet is a second among six randomly selected goblets is 0.3888.

(b) The probability that at least two goblet is a second among six randomly selected goblets is 0.1776.

(c) The probability that at most five must be selected to find four that are not seconds is 0.9453.

Step-by-step explanation:

Let X = number of seconds in the batch.

The probability of the random variable X is, p = 0.31.

The random variable X follows a Binomial distribution with parameters n and p.

The probability mass function of X is:

$P(X=x)={n\choose x}p^{x}(1-p)^{n-x};\ x=0,1,2,3...$

(a)

Compute the probability that only one goblet is a second among six randomly selected goblets as follows:

$P(X=1)={6\choose 1}0.13^{1}(1-0.13)^{6-1}\\=6\times 0.13\times 0.4984\\=0.3888$

Thus, the probability that only one goblet is a second among six randomly selected goblets is 0.3888.

(b)

Compute the probability that at least two goblet is a second among six randomly selected goblets as follows:

P (X ≥ 2) = 1 - P (X < 2)

$=1-{6\choose 0}0.13^{0}(1-0.13)^{6-0}-{6\choose 1}0.13^{1}(1-0.13)^{6-1}\\=1-0.4336+0.3888\\=0.1776$

Thus, the probability that at least two goblet is a second among six randomly selected goblets is 0.1776.

(c)

If goblets are examined one by one then to find four that are not seconds we need to select either 4 goblets that are not seconds or 5 goblets including only 1 second.

P (4 not seconds) = P (X = 0; n = 4) + P (X = 1; n = 5)

$={4\choose 0}0.13^{0}(1-0.13)^{4-0}+{5\choose 1}0.13^{1}(1-0.13)^{5-1}\\=0.5729+0.3724\\=0.9453$

Thus, the probability that at most five must be selected to find four that are not seconds is 0.9453.

8 0

3 years ago

2. A chemist has a 25% and a 50% acid solution. How

AnnZ [28]

Answer:

x is mL of 25% acid and y is mL of 50% acid

We set up 2 equations:

A) x + y = 250

B) .25 x + .50y = .35 * 250 which equals

B) .25x + .50y = 87.50 Multiplying A) by -.5

A) -.5x -.5y = -125 adding the equations we get

-.25x = -37.50

x = 150 mL

y = 100 mL

Source: http://www.1728.org/mixture.htm

Step-by-step explanation:

7 0

3 years ago

If y=6 when x=40 find x when y=24

Yanka [14]

Answer:

160

Step-by-step explanation:

24/6=4

4 x 40 = 160

x is 160 when y is 24

4 0

2 years ago

Read 2 more answers

Determine the factors of x2 − 12x − 20.

FrozenT [24]

Answer:

Step-by-step explanation:

Synthetic division is one way to determine whether or not a given number is a root of the quadratic. x^2 − 12x − 20 can be rewritten as x^2 - 12x + 36 - 36 - 20, or (x - 6)^2 - 56, which does not have integer solutions:

(x - 6)^2 - 56 = 0 becomes (x - 6)^2 = 56, which works out to x - 6 = ± 2√14.

None of the possible roots suggested in this problem turns out to be an actual root.

correct response: PRIME

3 0

3 years ago

If h(x) = 4x – 3 and p(x) = x2 – 3x, find p(-3) 18 0 -3

navik [9.2K]

Answer: p(-3)=18

Step-by-step explanation:

To find p(-3), you plug -3 into p(x) and solve.

p(-3)=(-3)²-3(-3) [exponent]

p(-3)=9-3(-3) [multiply]

p(-3)=9+9 [add]

p(-3)=18

Now we found that p(-3)=18.

7 0

3 years ago