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Firlakuza [10]
3 years ago
8

How soap is made? what are the measurements that have to be taken in the process?​

Chemistry
2 answers:
vfiekz [6]3 years ago
8 0

Answer:

Handcrafted soaps made from scratch require three ingredients to become soap: oil (animal or vegetable oil, not petroleum-based oil), water and lye. These three ingredients, mixed together in correct proportions, combine and chemically change into soap - a process called "saponification".

Dmitry_Shevchenko [17]3 years ago
6 0
<h2>Hey Sharon! :) </h2>

<h3>Q) How soap is made? </h3>
  • The oil is from an animal or plant, while the alkali is a chemical called lye. When oil and lye are combined and heated, the result is soap

<h3>Q) What are the measurements that have taken in the process? </h3>

  • Step 1: Melt and Mix the Oils. Weigh out your solid oils and melt them in a saucepan over a low heat. ...
  • Step 2: Mix the Water and Lye. ...
  • Step 3: Mix the Oils with the Lye Water. ...
  • Step 4: Bring the Soap Mix to Trace. ...
  • Step 5: Add to the Mold. ...
  • Step 6: Leave to Rest.

<h3>Measurements for making a Soap:</h3>

  • 4.75 ounces olive oil.

  • 4.75 ounces coconut oil.

  • 4.75 ounces soybean oil.

  • 2.5 ounces lye beads*

  • 5.75 ounces water.

<h2>Hope it help you</h2>
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Answer:

Explanation:

ndicator species (IS) are animals, plants, or microorganism used to monitor changes in our environment. For example, they can tell us about the impact of pollution on an ecosystem, or how well an impaired environment is being managed or restored.

5 0
3 years ago
A 32.5 g iron rod, initially at 22.4 ∘C, is submerged into an unknown mass of water at 63.0 ∘C, in an insulated container. The f
a_sh-v [17]

Answer:

m_{H_2O}=39.0g

Explanation:

Hello,

In this case, is possible to infer that the thermal equilibrium is governed by the following relationship:

\Delta H_{iron}=-\Delta H_{H_2O}\\m_{iron}Cp_{iron}(T_{eq}-T_{iron})=-m_{H_2O}Cp_{H_2O}(T_{eq}-T_{H_2O})

Thus, both iron's and water's heat capacities are: 0.444 and 4.18 J/g°C respectively, so one solves for the mass of water as shown below:

m_{H_2O}=\frac{m_{iron}Cp_{iron}(T_{eq}-T_{iron})}{-Cp_{H_2O}(T_{eq}-T_{H_2O}} \\\\m_{H_2O}=\frac{32.5g*0.444\frac{J}{g^0C}*(59.7-22.4)^0C}{-4.18\frac{J}{g^0C}*(59.7-63.0)^0C} \\\\m_{H_2O}=39.0g

Best regards.

8 0
3 years ago
A sample of 0.600 mol of a metal m reacts completely with excess fluorine to form 46.8 g of mf2. how many moles of f are in the
oksian1 [2.3K]
The balanced chemical reaction is expressed as:

M + F2 = MF2

To determine the moles of the element fluorine present in the product, we need to determine the moles of the product formed from the reaction and relate this value to the ratio of the elements in MF2. We do as follows:

moles MF2 produced = 0.600 mol M ( 1 mol MF2 / 1 mol M ) = 0.600 mol MF2
molar mass MF2 = 46.8 g MF2 / 0.6 mol MF2 = 78 g/mol
moles MF2 = 46.8 g ( 1 mol / 78 g ) = 0.6 mol
moles F = 0.6 mol MF2 ( 2 mol F / 1 mol MF2 ) = 1.2 moles F
6 0
3 years ago
What is the cell potential of an electrochemical cell that has the half-reactions shown below?
Karo-lina-s [1.5K]

Answer:

E°(Ag⁺/Fe°) = 0.836 volt

Explanation:

3Ag⁺ + 3e⁻ => Ag°;            E° = +0.800 volt

Fe° => Fe⁺³ + 3e⁻ ;             E° = -0.036 volt

_________________________________

Fe°(s) + 3Ag⁺(aq) => Fe⁺³(aq) + 3Ag°(s) ...    

E°(Ag⁺/Fe°) = E°(Ag⁺) - E°(Fe°) = 0.800v - ( -0.036v) = 0.836 volt

4 0
3 years ago
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