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Answer:
Average atomic mass of X is 10.2 amu.
Explanation:
Given data:
Percentage abundance of X-10 = 80%
Percentage abundance of X-11 = 20%
Average atomic mass of X = ?
Solution:
Average atomic mass of X = (abundance of 1st isotope × its atomic mass) +(abundance of 2nd isotope × its atomic mass) / 100
Average atomic mass of \X = (80×10)+(20×11) /100
Average atomic mass of X = 800 + 220 / 100
Average atomic mass of \X = 1020 / 100
Average atomic mass of X = 10.2 amu
Pv=nRT
where,p=199, R(constant)=8.314, V=4.67 T=30C=293K
n=pv/RT=0.38 moles
Their masses are identical because both of them weight 1kg. Only their volume is different.
Answer:
uh?
Explanation:
if you know about them, you will know which one did what to the crime scene. and you can use some chemicals to preserve evidence.