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djyliett [7]
2 years ago
9

Point T is on a segment with endpoints R(5, 10) and V(11, 4). Point T divides the segment such that RT:TV is 5:1. What are the c

oordinates of T?
Mathematics
1 answer:
inessss [21]2 years ago
7 0

We want to find a point on a segment such that the point divides the segment in the ratio 5:1

We will find that the point T is (6, 9)

The general formula for the point T that divides a segment whose endpoints are (x₁, y₁) and (x₂, y₂) such that separates the segment in the ratio j:k is given by:

T = (\frac{j*x_1 + k*x_2}{j + k} , \frac{j*y_1 + k*y_2}{j + k})

Here we have the endpoints (5, 10) and (11, 4), and we know that the ratio is 5:1

Then we can just use the above formula to get:

T = (\frac{5*5 + 1*11}{5 + 1} , \frac{5*10 + 1*4}{5 + 1}) = (\frac{36}{6} , \frac{54}{6} ) = (6, 9)

If you want to learn more, you can read:

brainly.com/question/17204382

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5. The Inland Revenue department claims it takes an average of 6 hours to complete a tax form. Assuming the time to complete the
forsale [732]

Answer:

i) 90.82% of the people can complete the form in more than 5 hours

ii) The probability that the sample mean is less than 6.5 hours is 0.9986 (99.86%)

Step-by-step explanation:

* Lets explain how to sole the problem

- The average time to complete a tax form is 6 hours

- Assuming the time to complete the form is normally distributed with a

 standard deviation of 45 minutes

∵ 1 hour = 60 minutes

∴ 45 minutes = 45/60 = 0.75 hour

∴ The standard deviation is 0.75 hour

i)

- We need to know the percentage of the people who complete the

 form in more than 5 hours

* Lets use z-score to find the probability

∵ z-score = (x - μ)/σ , where

# x is the score

# μ is the mean

# σ is the standard deviation

∵ μ = 6 , σ = 0.75 , x = 5

∴ z=\frac{5-6}{0.75}=-1.33

- Use the normal distribution table to find the corresponding area

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∵ The corresponding area of -1.33 = 0.09176

∵ P(x > 5) = 1 - P(z > -1.33)

∴ P(x > 5) = 1 - 0.09176 = 0.90824

- Change it to percentage by multiply it by 100%

∴ P(x > 5) = 0.90824 × 100% = 90.82%

∴ 90.82% of the people can complete the form in more than 5 hours

ii)

- A sample of 20 taxpayers are selected

- We need to know the probability that the sample mean is less

 than 6.5 hours

- The sample means is called M

- The standard deviation of the distribution of sample means is

  called σM  where σM = σ/√n , where σ is the standard deviation and

  n is the sample size

- z-score = (M - μ)/σM, where μ is the mean of the population  

∵ μ = 6 , σ = 0.75 , n = 20 ,  M = 6.5 hours

∴ σM = \frac{0.75}{\sqrt{20}}=0.1677

∴ z=\frac{6.5-6}{0.1677}=2.98

- Use the normal distribution table to find the corresponding area

 of z-score 2.98

∵ The corresponding area of 2.98 is 0.99856

∵ P(x < 6.5) = P(z < 2.98)

∴ P(x < 6.5) = 0.99856

∴ The probability that the sample mean is less than 6.5 hours

   is 0.9986 (99.86%)

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