Answer:
![\huge\boxed{Q = \sqrt{A+2a}}](https://tex.z-dn.net/?f=%5Chuge%5Cboxed%7BQ%20%3D%20%5Csqrt%7BA%2B2a%7D%7D)
Step-by-step explanation:
![A = Q^2 -2a](https://tex.z-dn.net/?f=A%20%3D%20Q%5E2%20-2a)
Adding 2a to both sides
![Q^2 = A+2a](https://tex.z-dn.net/?f=Q%5E2%20%3D%20A%2B2a)
Taking sqrt on both sides
![Q = \sqrt{A+2a}](https://tex.z-dn.net/?f=Q%20%3D%20%5Csqrt%7BA%2B2a%7D)
Answer:
pet smart sell
Step-by-step explanation:
because it is cheaper than other sell
To start out, notice that you want the percent of voters that chose candidate A,
not the percent of the class that chose candidate A.
Your fraction should be "number that chose candidate A" out of "number of voters," which is the same thing as saying: "number that chose candidate A" divided by "number of voters"1) The numerator of the fraction should be the number of votes for candidate A, which is 11.
2) The denominator of the fraction should be the number of voters. You're told that "t<span>here were 11 votes for Candidate A and 15 votes for Candidate B," so there are:
</span>
![11 + 15 \: total \: votes](https://tex.z-dn.net/?f=11%20%2B%2015%20%5C%3A%20total%20%5C%3A%20votes)
3) Finally put parts 1 and 2 together into a fraction and multiply by 100 to get your percent. That is your final answer:
![\frac{11}{11+15} \times 100](https://tex.z-dn.net/?f=%20%5Cfrac%7B11%7D%7B11%2B15%7D%20%20%5Ctimes%20100)
----
Answer: Top right choice, ![\frac{11}{11+15} \times 100](https://tex.z-dn.net/?f=%20%5Cfrac%7B11%7D%7B11%2B15%7D%20%5Ctimes%20100)
<span>
</span>
Step-by-step explanation:
<em>2</em><em>+</em><em>1</em><em>9</em><em>=</em><em>7x</em>
<em>2</em><em>1</em><em>=</em><em>7x</em>
<em>21</em><em>÷</em><em>7</em><em>=</em><em>7x</em><em>÷</em><em>7</em>
<em>3</em><em>=</em><em>x</em>
<em>.</em><em>.</em>
<u>Answer</u>
6,122 hm
<u>Explanation</u>
You can carry out operations on the like terms only. So convert all units to one unit.
I will convert them to dam
1 km =100 dam
73 km = 73 × 100
=7,300 dam
11 km = 11× 100
1100 dam
1 hm = 10 dam
47 hm = 47 × 10
= 470 dam
55 hm = 55× 10
= 550 dam
73km 47hm 2dam - 11km 55hm = (7300+ 470+2) - (1100+550)
= 7,772 - 1,650
= 6,122 hm