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3 years ago

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Mathematics

1 answer:

vaieri [72.5K]3 years ago

8 0

Answer and Step-by-step explanation:

Given Asin(wt + phi), we know that sin (A + B) = sinAcosB + sinBcosA. This means:

Asin(wt + phi) = Asin(wt)cos(phi) + Asin(phi)cos(wt).

Let Acos(phi) = c2 and Asin(phi) = c1 we have:

Asin(wt + phi) = c2sin(wt) + c1cos(wt)

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3 years ago

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Mazyrski [523]

Answer:

Hello,

Step-by-step explanation:

y-intercept: x=0 ,f(0)=-10

$x^3-8x^2+17x-10\\\\=x^3-5x^2-3x^2+15x+2x-10\\\\=x^2(x-5)-3x(x-5)+2(x-5)\\\\=(x-5)(x^2-3x+2)\\\\=(x-5)(x^2-x-2x+2)\\\\=(x-5)(x(x-1)-2(x-1))\\\\=(x-5)(x-1)(x-2)\\$

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3 years ago

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julsineya [31]

Answer:

4/2, 2/7, 1/2, 5/6 is your answer

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just olya [345]

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Lim<br> x->infinity (1+1/n)

FrozenT [24]

Answer:

$^{ \lim}_{n \to \infty} (1+\frac{1}{n})=1$

Step-by-step explanation:

We want to evaluate the following limit.

$^{ \lim}_{n \to \infty} (1+\frac{1}{n})$

We need to recall that, limit of a sum is the sum of the limit.

So we need to find each individual limit and add them up.

$^{ \lim}_{n \to \infty} (1+\frac{1}{n})=^{ \lim}_{n \to \infty} (1) +^{ \lim}_{n \to \infty} \frac{1}{n}$

Recall that, as $n\rightarrow \infty,\frac{1}{n} \rightarrow 0$ and the limit of a constant, gives the same constant value.

This implies that,

$^{ \lim}_{n \to \infty} (1+\frac{1}{n})= 1 +0$

This gives us,

$^{ \lim}_{n \to \infty} (1+\frac{1}{n})= 1$

The correct answer is D

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3 years ago