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givi [52]
3 years ago
15

Help

Mathematics
1 answer:
vaieri [72.5K]3 years ago
8 0

Answer and Step-by-step explanation:

Given Asin(wt + phi), we know that sin (A + B) = sinAcosB + sinBcosA. This means:

Asin(wt + phi) = Asin(wt)cos(phi) + Asin(phi)cos(wt).

Let Acos(phi) = c2 and Asin(phi) = c1 we have:

Asin(wt + phi) = c2sin(wt) + c1cos(wt)

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PLS HELP 50 POINTS
natali 33 [55]

Answer:

f(x+1)=(5/6)f(x)on:          Five-sixths Superscript f (x)

EXPLANATION:

The defining characteristic of a geometric sequence is that each term is a constant multiple of the previous term, called the common ratio denoted r in the rules for geometric equations.

625/750=750/900=etc=r=5/6

4 0
3 years ago
Read 2 more answers
Daniel has a coupon for $1.44 off
Art [367]

Answer:

Daniel will save $1.18

Step-by-step explanation:

First, find the cost of the name-brand flour with the coupon:

Subtract 1.44 from the original price of 9.12:

9.12 - 1.44

= 7.68

So, the price of the name-brand flour with the coupon is $7.68

Now, find how much he will save by finding the difference between this price and the price of the store brand flour:

8.86 - 7.68

= 1.18

So, Daniel will save $1.18

3 0
2 years ago
What is the result of substituting for y in the bottom equation<br> y=x+3<br> y=x^2+2x-4
8_murik_8 [283]

The solutions are (2.1925, 5.1925) and (-3.1925, -0.1925)

<em><u>Solution:</u></em>

Given that,

y = x + 3 ------- eqn 1\\\\y = x^2 + 2x - 4  ----- eqn 2

<em><u>We have to substitute eqn 1 in eqn 2</u></em>

x + 3 = x^2 + 2x - 4

\mathrm{Switch\:sides}\\\\x^2+2x-4=x+3\\\\\mathrm{Subtract\:}3\mathrm{\:from\:both\:sides}\\\\x^2+2x-4-3=x+3-3\\\\\mathrm{Simplify}\\\\x^2+2x-7=x\\\\\mathrm{Subtract\:}x\mathrm{\:from\:both\:sides}\\\\x^2+2x-7-x=x-x\\\\\mathrm{Simplify}\\\\x^2+x-7=0

\mathrm{Solve\:with\:the\:quadratic\:formula}\\\\\mathrm{For\:a\:quadratic\:equation\:of\:the\:form\:}ax^2+bx+c=0\mathrm{\:the\:solutions\:are\:}\\\\x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}\\\\\mathrm{For\:}\quad a=1,\:b=1,\:c=-7\\\\x =\frac{-1\pm \sqrt{1^2-4\cdot \:1\left(-7\right)}}{2\cdot \:1}

x = \frac{-1 \pm \sqrt{ 1 + 28}}{2}\\\\x = \frac{ -1 \pm \sqrt{29}}{2}

x = \frac{ -1 \pm 5.385 }{2}\\\\We\ have\ two\ solutions\\\\x = \frac{ -1 + 5.385 }{2}\\\\x = 2.1925

Also\\\\x = \frac{ -1 - 5.385 }{2}\\\\x = -3.1925

Substitute x = 2.1925 in eqn 1

y = 2.1925 + 3

y = 5.1925

Substitute x = -3.1925 in eqn 1

y = -3.1925 + 3

y = -0.1925

Thus the solutions are (2.1925, 5.1925) and (-3.1925, -0.1925)

6 0
3 years ago
X+9=24 how to solve for x
rodikova [14]
You can easily do just one step to get the value of x.

x + 9 =24            subtract 9 from both sides

x + 9 - 9 = 24 - 9

Simplify:

x = 15


I hope I helped you.



5 0
3 years ago
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What is the area of the triangle? ​
beks73 [17]
The area of a triangle is 180
4 0
3 years ago
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