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3 years ago

The ratio of boys to girls in a group is 3:1. If there are 28 more boys than girls, work out how many people there are in total.

Mathematics

1 answer:

puteri [66]3 years ago

3 0

Answer:

84:56, I think?

3 x 28 for the boys then minus 28 for the girls

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Dori spent 1/5 of her money on a toy boat and scuba goggles. The toy boat cost 2 times as much as the goggles. The toy boat cost

Korolek [52]

Answer:

Dori has $48 left.

Step-by-step explanation:

The boat costs twice as much as the goggles, divide 8 by 2 to find the price of the goggles. The price of the goggles is $4.

Add $8 and $4 to get $12. This is the total money Dori spent.

Since this is 1/5 of her money, multiply $12 by 5 to get $60. This is the money Dori had.

Subtract the $12 from the $60 to get $48. This is the money Dori has left.

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3 years ago

How do you find the m and b in the problem y=-x+1?

inysia [295]

In Y=mx+b:

m=slope. That is found by using this formula y2-y1/x2-x1

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3 years ago

Como dividir 8.2 por 2.87

lakkis [162]

It would equal 11.07. it is right

3 0

4 years ago

Read 2 more answers

Solve this quadratic equation using the quadratic formula. 2x2 - 10x + 7 = 0

frez [133]

Answer:

Step-by-step explanation:

2x^2-10x+7 A=1, B=-10. C=7

-(-10)±√-10^2-4(1)(7)

------------------------------

2(1)

10±√100-28

----------------

10±√72

-----------

10±8.485281374

10+8.485281374 =9.24

10-8.485281374 =0.76

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4 years ago

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A random sample of 31 charge sales showed a sample standard deviation of $50. a 90% confidence interval estimate of the populati

Marysya12 [62]

The $100(1-\alpha)\%$ confidence interval of a standard deviation is given by:

$\sqrt{ \frac{(n-1)s^2}{\chi^2_{1- \frac{\alpha}{2} } }} \leq\sigma\leq\sqrt{ \frac{(n-1)s^2}{\chi^2_{\frac{\alpha}{2} } }}$

Given a sample size of 31 charge sales, the degree of freedom is 30 and for 90% confidence interval,

$\chi^2_{1- \frac{\alpha}{2} }=43.773 \\ \\ \chi^2_{\frac{\alpha}{2} }=18.493$

Therefore, the 90% confidence interval for the standard deviation is given by

$\sqrt{ \frac{(31-1)50^2}{43.773 }} \leq\sigma\leq\sqrt{ \frac{(31-1)50^2}{18.493 }} \\ \\ \Rightarrow\sqrt{ \frac{(30)2500}{43.773 }} \leq\sigma\leq\sqrt{ \frac{(30)2500}{18.493 }} \\ \\ \Rightarrow\sqrt{ \frac{75000}{43.773 }} \leq\sigma\leq\sqrt{ \frac{75000}{18.493 }} \\ \\ \Rightarrow \sqrt{1713.38} \leq\sigma\leq \sqrt{4055.59} \\ \\ \Rightarrow41.4\leq\sigma\leq63.7$

3 0

3 years ago