If two figures are similar their angles are

Mathematics

1 answer:

NISA [10]3 years ago

6 0

Answer:

i really dont know

Step-by-step explanation:

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Someone help please! Determine the intercept of the line that passes through the following points

storchak [24]

Answer:

x: (-5.0)

y: (0, -17.5)

Step-by-step explanation:

The x-intercept of the line is when y=0. In the table is the point (-5,0). This is the x-intercept.

To find the y-intercept, find when x=0. Write an equation for the table in y=mx + b. Find the slope between two points first.

$m = \frac{y_2-y_1}{x_2-x_1} = \frac{7-0}{-7--5} =\frac{7}{-7+5}=-\frac{7}{2} = -3.5$

The slope is -3.5. So the equation is

y - 7 = -3.5(x--7)

y - 7 = -3.5 (x+7)

y - 7 = -3.5x - 24.5

y = 3.5x - 17.5

Since it is in y=mx+b, b= -17.5 and this is the y-intercept.

5 0

3 years ago

Write an equation of the line that passes through the given point and is (a) parallel and (b) perpendicular to the given line.

inessss [21]

Answer:

(a). y = 3x - 11 ; (b). y = $-\frac{1}{3}$ x - 1

Step-by-step explanation:

Parallel lines have the same slopes

Slopes of perpendicular lines are opposite reciprocals.

(3, - 2)

The slope of given line is 3

(a). Equation of ║ line is

y + 2 = 3(x - 3)

y = 3x - 11

(b). Slope of perpendicular line is $-\frac{1}{3}$

y + 2 = $-\frac{1}{3}$ (x - 3)

y =  $-\frac{1}{3}$  x - 1

5 0

3 years ago

Read 2 more answers

A new test has been developed to detect a particular type of cancer. The test must be evaluated before it is put into use. A med

Troyanec [42]

The tree diagram of the problem above is attached
There are four outcomes of the two events,

First test - Cancer, Second Test - Cancer, the probability is 0.0396
First test - Cancer, Second Test - No Cancer, the probability is 0.0004
First test - No Cancer, Second Test - There is cancer, the probability is 0.0096
First test - No cancer, Second Test - No cancer, the probability is 0.9054

The probability of someone picked at random has cancer given that test result indicates cancer is $\frac{0.0396}{0.0396+0.0096}= \frac{33}{41}$

The probability of someone picked at random has cancer given that test result indicates no cancer is $\frac{0.0396}{0.0004+0.9504} = \frac{99}{2377}$