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eduard
3 years ago
14

Chec

Mathematics
1 answer:
nexus9112 [7]3 years ago
8 0

Answer:

Functions: y = -x + 11, y = 2x^2 - 6x + 4, y = 7

Not Functions: x = 3, x^2 + y^2 = 81, y^2 = -5x - 12

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Please help me giving out 5 points each
Kay [80]

the answer is B...i swear its B

8 0
3 years ago
Read 2 more answers
12345 what is the answer if you multiply 1x2x3x4x5 and do the same with subtraction, addition and devision, in that order. Then
Alexandra [31]

Well, we just need to perform the operations:

  • Multiplication: 1\cdot 2 \cdot 3 \cdot 4 \cdot 5 = 120
  • Subtraction: 1-2-3-4-5 = -13
  • Addition: 1+2+3+4+5 = 15
  • Division: 1 \div 2 \div 3 \div 4 \div 5 = \frac{1}{120}

So, if you add all the numbers together you get

120-13+15+\dfrac{1}{120} = 122 + \dfrac{1}{120}

Or, if you prefer,

\dfrac{1681}{120}

8 0
3 years ago
What is a capacity of 25 fl oz more than a capacity of 3 cups
nata0808 [166]
I’m guessing 2 cups or something idk
7 0
3 years ago
WHY must the same operation be performed on both sides of an equation? ​
lys-0071 [83]

Answer:When you are given a problem, the two sides are equal, so they are equally weighted. As long as you do the same thing on both sides, they remain the same weight. The only way that one side can become "more weight" on a side is if you make a math mistake, and thus the answer would not satisfy the original equation

Step-by-step explanation:looked it up... have a good day!

8 0
3 years ago
Please help! It’s Saturday and I only have this question left on my digital worksheet!
Natalija [7]

Answer:

<h2>The answer is option C</h2>

Step-by-step explanation:

<h3>\frac{ {6}^{ - 3} }{ {6}^{5} }</h3>

Using the rules of indices

Since the bases are the same and are dividing we subtract the exponents

That's

<h3>\frac{ {a}^{x} }{ {a}^{y} }  =  {a}^{x - y}</h3>

So we have

<h3>\frac{ {6}^{ - 3} }{ {6}^{5} }  =  {6}^{ -  3 - 5}  =  {6}^{ - 8}</h3>

Using the rules of indices

<h3>{x}^{ - y}  =  \frac{1}{ {x}^{y} }</h3>

So we have the final answer as

<h2>\frac{1}{ {6}^{8} }</h2>

Hope this helps you

4 0
3 years ago
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