Answer:
The correct answer is 169.56 g/mol.
Explanation:
Based on the given information, the mass of Ag deposited is 1.24 g, and the mass of unknown metal X deposited in another cell is 0.650 g. The number of moles of electrons can be determined as,
= 1.24 g Ag * 1mol Ag/107.87 g/mol Ag * 1 mol electron/1 mol Ag ( the molecular mass of Ag is 107.87 g/mol)
= 0.0115 mole of electron
The half cell reaction for the metal X is,
X^3+ (aq) + 3e- = X (s)
From the reaction, it came out that 3 faraday will reduce one mole of X^3+.
The molar mass of X will be,
= 0.650 g/0.0115 *3 mol electron/1 mol
= 56.52 * 3
= 169.56 g/mol
Answer:
Soil is heterogeneous mixture of sand particles of different sizes, shape and of different compositions.
Explanation:
Homogeneous mixtures are defined as the mixtures in which components are evenly spread throughout the solution. The size and shape of the particles are similar in these mixtures.
For example : alloys, salt solution.
Heterogeneous mixtures are defined as the mixtures in which component are unevenly spread throughout the solution. The size and shape of the particles differ in these mixtures.
For example : sand in a water, soil etc.
Brass is an alloy homogeneous mixture of metals.
Air is a homogeneous mixture of gases.
Coffee with sugar stirred in is also homogeneous mixture.
Soil is a heterogeneous mixture of sand particles of different sizes, shape and of different compositions.
The question requires that you assume complete ionization of the compound. This is:
(NH4)2 SO4 → 2 NH4 (+) + SO4 (2-)
Then, 1 mol of (NH4)2 SO4 produces 3 moles of ions: 2 moles of NH4 (+) and 1 mol of SO4 (2-)
=> 0.26 * 2 moles of NH4(+) = 0.52 moles of NH4 (+)
0.26 * 1 mol of SO4 (2-) = 0.26 moles of SO4 (2-).
Answer: 0.52 moles of ammonium ions and 0.26 moles of sulfate.ions.
