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Studentka2010 [4]
3 years ago
12

Helpppppopoppoppppppppp

Mathematics
1 answer:
notka56 [123]3 years ago
6 0

Answer:

0.19

Step-by-step explanation:

i am not so sure but it's my opinion

8[14-(7+4×4)]

__________

1-121-1-8

8[14-[44]

_______

-120-1-8

8[-30]

_____

119-8

8-30

____

111

-22

___

111

✓ 0.19

don't blame me if it is wrong lol

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State the domain of the function. (5 points) 2 1 1 3 -6​
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Answer:

-2, 1, 2, 3, 4

Step-by-step explanation:

The domain is the x values of the graph.

8 0
3 years ago
Can someone help me please
Nat2105 [25]
Ithe diameter would be about 5
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Which is greater 5/8 or 5/12?
ElenaW [278]
5/8 is greater than 5/12
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Leftover Expression
Mumz [18]

The second leftover expression is not o(a+b). It is 6(a + b). I have attached the correct question to depict that.

Answer:

The equivalent expressions are;

8a + 2 and 6a + 6b

Step-by-step explanation:

The two leftover expressions are given as;

2(4x + 1) and 6(a + b)

In algebra, equivalent expressions are simply those expressions which when simplified, give the same resulting expression as the initial one.

Thus simply means expanding or collecting like times to make it clearer.

Now, in our question, like terms have already been collected. This means that to find an equivalent expression, we will just expand the bracket.

Thus;

2(4x + 1) will be expanded by using the 2 outside the bracket to multiply the terms inside the bracket. This gives;

8x + 2

Similarly,

6(a + b) will be expanded by using the 2 outside the bracket to multiply the terms inside the bracket. This gives;

6a + 6b

Thus;

The equivalent expressions are;

8a + 2 and 6a + 6b

4 0
3 years ago
Given points A (1, 2/3), B (x, -4/5), and C (-1/2, 4) determine the value of x such that all three points are collinear
AlladinOne [14]

Answer:

x=\frac{83}{50}

Step-by-step explanation:

we know that

If the three points are collinear

then

m_A_B=m_A_C

we have

A (1, 2/3), B (x, -4/5), and C (-1/2, 4)

The formula to calculate the slope between two points is equal to

m=\frac{y2-y1}{x2-x1}

step 1

Find the slope AB

we have

A(1,\frac{2}{3}),B(x,-\frac{4}{5})

substitute in the formula

m_A_B=\frac{-\frac{4}{5}-\frac{2}{3}}{x-1}

m_A_B=\frac{\frac{-12-10}{15}}{x-1}

m_A_B=-\frac{22}{15(x-1)}

step 2

Find the slope AC

we have

A(1,\frac{2}{3}),C(-\frac{1}{2},4)

substitute in the formula

m_A_C=\frac{4-\frac{2}{3}}{-\frac{1}{2}-1}

m_A_C=\frac{\frac{10}{3}}{-\frac{3}{2}}

m_A_C=-\frac{20}{9}

step 3

Equate the slopes

m_A_B=m_A_C

-\frac{22}{15(x-1)}=-\frac{20}{9}

solve for x

15(x-1)20=22(9)

300x-300=198

300x=198+300

300x=498

x=\frac{498}{300}

simplify

x=\frac{83}{50}

8 0
3 years ago
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