All categories

3 years ago

What is one difference between fixed-rate mortgages and variable-rate mortgages?

Mathematics

2 answers:

STALIN [3.7K]3 years ago

5 0

Answer:

A variable interest rate loan is a loan where the interest charged on the outstanding balance fluctuates based on an underlying benchmark or index that periodically changes. A fixed interest rate loan is a loan where the interest rate on the loan remains the same for the life of the loan.

<h3><u>PLEASE</u><u> MARK</u><u> ME</u><u> BRAINLIEST</u><u>.</u></h3>

Shalnov [3]3 years ago

5 0

Answer:

<h2>Fixed-rate financing means the interest rate on your loan does not change over the life of your loan. ... With a variable-rate loan, the interest rate on the loan changes as the index rate changes, meaning that it could go up or down. Because your interest rate can go up, your monthly payment can also go up.</h2>

You might be interested in

Select the correct location on the table.

enot [183]

Answer:

someone plz answer this I need the answer

Step-by-step explanation:

8 0

3 years ago

Slope is –2 & (5, 3) is on the line.<br> Y-Intercept:<br> Equation of the line (no spaces):

GREYUIT [131]

Answer:

The y intercept is (0,13)

The equation of the line is y = -2x+13

Step-by-step explanation:

The slope intercept form of a line is

y = mx+b where m is the slope and b is the y intercept

y = -2x+b

Substituting the point

3 = -2(5) +b

3 = -10 +b

Add 10 to each side

13 =b

The y intercept is (0,13)

The equation of the line is y = -2x+13

5 0

3 years ago

A cylindrical rain barrel has a radius of 2 feet and holds a total of 30 cubic feet of water. How tall is the rain barrel? Use 3

enot [183]

Answer:

2.39 feet

Step-by-step explanation:

we know that

The volume of a cylinder is equal to

$V=\pi r^{2}h$

where

r is the radius of the base of the cylinder

h is the height of the cylinder

we have

$V=30\ ft^3$

$r=2\ ft$

$\pi =3.14$

substitute

$30=(3.14)(2^{2})h$

Solve for h

$30=(3.14)(4)h$

$h=30/12.56$

$h=2.39\ ft$

7 0

3 years ago

(06.02 mc) the equation of line cd is y=3x-3. Write an equation of a line perpendicular to line cd in slope intercept form that

Fynjy0 [20]

Answer:

y = - $\frac{1}{3}$ x + 2

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

y = 3x - 3 ← is in slope- intercept form

with slope m = 3

Given a line with slope m then the slope of a line perpendicular to it is

$m_{perpendicular}$ = - $\frac{1}{m}$ = - $\frac{1}{3}$ , hence

y = - $\frac{1}{3}$ x + c ← is the partial equation of the perpendicular line

To find c substitute (3, 1) into the partial equation

1 = - 1 + c ⇒ c = 1 + 1 = 2

y = - $\frac{1}{3}$ x + 2 ← equation of perpendicular line

6 0

3 years ago

Read 2 more answers

Which expression is equivalent to (16 x Superscript 8 Baseline y Superscript negative 12 Baseline) Superscript one-half?.

loris [4]

To solve the problem we must know the Basic Rules of Exponentiation.

<h2>Basic Rules of Exponentiation</h2>

$x^ax^b = x^{(a+b)}$
$\dfrac{x^a}{x^b} = x^{(a-b)}$
$(a^a)^b =x^{(a\times b)}$
$(xy)^a = x^ay^a$

$x^{\frac{3}{4}} = \sqrt[4]{x^3}= (\sqrt[3]{x})^4$

The solution of the expression is $\dfrac{4x^4}{y^6}$ .

<h2>Explanation</h2>

Given to us

$(16x^8y^{12})^{\frac{1}{2}}$

Solution

We know that 16 can be reduced to $2^4$ ,

$=(2^4x^8y^{12})^{\frac{1}{2}}$

Using identity $(xy)^a = x^ay^a$ ,

$=(2^4)^{\frac{1}{2}}(x^8)^{\frac{1}{2}}(y^{12})^{\frac{1}{2}}$

Using identity $(a^a)^b =x^{(a\times b)}$ ,

$=(2^{4\times \frac{1}{2}})\ (x^{8\times\frac{1}{2}})\ (y^{12\times{\frac{1}{2}}})$

Solving further

$=2^2x^4y^{-6}$

Using identity $\dfrac{x^a}{x^b} = x^{(a-b)}$ ,

$=\dfrac{2^2x^4}{y^6}$

$=\dfrac{4x^4}{y^6}$

Hence, the solution of the expression is $\dfrac{4x^4}{y^6}$ .

Learn more about Exponentiation:

brainly.com/question/2193820

8 0

2 years ago