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3 years ago

I need help wants 13x+2y-10-7y (you have to simplify it)

Mathematics

1 answer:

ira [324]3 years ago

8 0

Answer:

13x-5y-10

Step-by-step explanation:

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a tourist drove his car for the total of 17.5 hours while on a 3-day vacation on the first day he drove 4.5 hours in the second

AleksAgata [21]

Answer:

1.75 hours

Step-by-step explanation:

Time for day 1 : 4.5 hrs

Time for day 2: (4.5 ×2.5)

Time for day 3: let it be denoted by a variable ,say T.

Total Time= 17.5

(Time for day 1 ) + (Time for day 2) +(Time for day 3) =17.5

4.5 + (4.5×2.5) + T = 17.5

4.5+11.25+T =17.5

15.75+T=17.5

T=17.5-15.75

T= 1.75

7 0

3 years ago

What is the area of the figure?

Arada [10]

The area of the figure is 28 yd^2

4 0

3 years ago

Read 2 more answers

HELPPP PLEASEEEEEE!?!?!

DiKsa [7]

a straight line is 180 degrees so we can find C by subtracting 140 from 180

180-140 = 40 degrees

all 3 inside angles need to equal 180 so now we have

180 = 40 + (2x) + (x+2)

180 = 40 +3x +2

180=42+3x

138=3x

x= 138/3 = 46

check : 2x= 2*46 = 92

x+2 = 46+2 = 48

92 +48 +40 = 180

so x = 46 degrees

so angle B = 2x46 = 92 degrees

6 0

3 years ago

The number of pollinated flowers as a function of time in days can be represented by the function. f(x)

ratelena [41]

The average increase in the number of flowers pollinated per day between days 4 and 10 is 39, given that the number of pollinated flowers as a function of time in days can be represented by the function $f(x) = (3)^{\frac{x}{2} }$ .

In the question, we are asked for the average increase in the number of flowers pollinated per day between days 4 and 10, given that the number of pollinated flowers as a function of time in days can be represented by the function $f(x) = (3)^{\frac{x}{2} }$ .

To find the average increase in the number of flowers pollinated per day between days 4 and 10, we use the formula {f(10) - f(4)}/{10 - 4}.

First, we find the value of the function $f(x) = (3)^{\frac{x}{2} }$ , for f(10) and f(4).

$f(x) = (3)^{\frac{x}{2} }\\\Rightarrow f(10) = (3)^{\frac{10}{2} }\\\Rightarrow f(10) = 3^5 = 243$

$f(x) = (3)^{\frac{x}{2} }\\\Rightarrow f(4) = (3)^{\frac{4}{2} }\\\Rightarrow f(10) = 3^2 = 9$

Thus, the average increase

= {f(10) - f(4)}/{10 - 4},

= (243 - 9)/(10 - 4),

= 234/6

= 39.

Thus, the average increase in the number of flowers pollinated per day between days 4 and 10 is 39, given that the number of pollinated flowers as a function of time in days can be represented by the function $f(x) = (3)^{\frac{x}{2} }$ .

Learn more about the average increase in a function at

brainly.com/question/7590517

#SPJ4

For complete question, refer to the attachment.