Ask question

Ask question

All categories

2 years ago

13

Please help !!! I will give 20 points to correct answer !!!!

2 answers:

Sonja [21]2 years ago

4 0

Answer:

the answer above the image

seropon [69]2 years ago

4 0

Answer:

a=-4/3, 14/3

Step-by-step explanation:

absolute value only makes the answer become positive whether the value inside is negative or positive.
so -3a+5=9 or -3a+5=-9 all works

-3a+5=9

-3a=4

a=-4/3

If -3a+5=-9

-3a=-14

a=14/3

You might be interested in

<img src="https://tex.z-dn.net/?f=%20%5Csqrt%5B6%5D%7Bx%20%7B%7D%5E%7B2%7Dy%20%7B%7D%5E%7B3%7D%20%20%7D%20" id="TexFormula1" tit

DIA [1.3K]

Answer:

6 x^2 y^3

Step-by-step explanation:

3 0

3 years ago

Turn this into numerical form -> one-half the sum of x and 12 Thank you!

ycow [4]

Answer: 1/2(x+12)

Step-by-step explanation: Sum is adding.

3 0

3 years ago

Triangle ABC was transformed using the rule (x, y) →(-y,

CaHeK987 [17]

Answer:

A the first one ( the rotation of 90 degree)

Step-by-step explanation:

Please mark as brainliest if it helps. I need to rank up.

3 0

2 years ago

Read 2 more answers

The following results come from two independent random samples taken of two populations.

photoshop1234 [79]

Answer:

$(a)\ \bar x_1 - \bar x_2 = 2.0$

$(b)\ CI =(1.0542,2.9458)$

$(c)\ CI = (0.8730,2.1270)$

Step-by-step explanation:

Given

$n_1 = 60$ $n_2 = 35$

$\bar x_1 = 13.6$ $\bar x_2 = 11.6$

$\sigma_1 = 2.1$ $\sigma_2 = 3$

Solving (a): Point estimate of difference of mean

This is calculated as: $\bar x_1 - \bar x_2$

$\bar x_1 - \bar x_2 = 13.6 - 11.6$

$\bar x_1 - \bar x_2 = 2.0$

Solving (b): 90% confidence interval

We have:

$c = 90\%$

$c = 0.90$

Confidence level is: $1 - \alpha$

$1 - \alpha = c$

$1 - \alpha = 0.90$

$\alpha = 0.10$

Calculate $z_{\alpha/2}$

$z_{\alpha/2} = z_{0.10/2}$

$z_{\alpha/2} = z_{0.05}$

The z score is:

$z_{\alpha/2} = z_{0.05} =1.645$

The endpoints of the confidence level is:

$(\bar x_1 - \bar x_2) \± z_{\alpha/2} * \sqrt{\frac{\sigma_1^2}{n_1}+\frac{\sigma_2^2}{n_2}}$

$2.0 \± 1.645 * \sqrt{\frac{2.1^2}{60}+\frac{3^2}{35}}$

$2.0 \± 1.645 * \sqrt{\frac{4.41}{60}+\frac{9}{35}}$

$2.0 \± 1.645 * \sqrt{0.0735+0.2571}$

$2.0 \± 1.645 * \sqrt{0.3306}$

$2.0 \± 0.9458$

Split

$(2.0 - 0.9458) \to (2.0 + 0.9458)$

$(1.0542) \to (2.9458)$

Hence, the 90% confidence interval is:

$CI =(1.0542,2.9458)$

Solving (c): 95% confidence interval

We have:

$c = 95\%$

$c = 0.95$

Confidence level is: $1 - \alpha$

$1 - \alpha = c$

$1 - \alpha = 0.95$

$\alpha = 0.05$

Calculate $z_{\alpha/2}$

$z_{\alpha/2} = z_{0.05/2}$

$z_{\alpha/2} = z_{0.025}$

The z score is:

$z_{\alpha/2} = z_{0.025} =1.96$

The endpoints of the confidence level is:

$(\bar x_1 - \bar x_2) \± z_{\alpha/2} * \sqrt{\frac{\sigma_1^2}{n_1}+\frac{\sigma_2^2}{n_2}}$

$2.0 \± 1.96 * \sqrt{\frac{2.1^2}{60}+\frac{3^2}{35}}$

$2.0 \± 1.96* \sqrt{\frac{4.41}{60}+\frac{9}{35}}$

$2.0 \± 1.96 * \sqrt{0.0735+0.2571}$

$2.0 \± 1.96* \sqrt{0.3306}$

$2.0 \± 1.1270$

Split

$(2.0 - 1.1270) \to (2.0 + 1.1270)$

$(0.8730) \to (2.1270)$

Hence, the 95% confidence interval is:

$CI = (0.8730,2.1270)$

8 0

3 years ago

Please help!!!! ASAP!!!

Nookie1986 [14]

2/4 = 3/6 is true.

First, simplify the fractions:

2/4 = 1/2

3/6 = 1/2

We see that 1/2 = 1/2, so 2/4 DOES equal 3/6.

6 0

2 years ago

Read 2 more answers