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3 years ago

What two areas of your body (related to the skeletal system) would be impacted by prolonged periods of sitting and typing

Physics

1 answer:

Naddik [55]3 years ago

3 0

Answer: Weak Legs and Glutes

Explanation: Cause ur legs go brrrrrr

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A boy is listening to the radio. The loudspeaker plays a musical note by vibrating 256 rimes esch second. How many times does th

Svet_ta [14]

Answer:

f_tympanum = 256 Hz.

Explanation:

The eardrum is the vibrating membrane of the human ear, it works by resonance, that is, an external stimulus (force) makes it vibrate, as the eardrum is extremely light it can vibrate at the same frequency of the incident sound.

Consequently if the incident vibration is f = 256 hz, the eardrum resonates at the same frequency

f_tympanum = 256 Hz.

As a reference the response of the eardrum goes from f = 20 Hz f = 20000 Hz

6 0

4 years ago

If you want to double the kinetic energy of a gas molecule, by what factor must you increase its momentum?A) 16B) 2^(1/2)

worty [1.4K]

Answer: $\sqrt{2}$

The linear momentum $p$ is given by the following equation:

$p=m.v$ (1)

Where $m$ is the mass and $v$ the velocity.

On the other hand, the kinetic energy $K$ is given by:

$K=\frac{p^{2}}{2m}$ (2)

Which is the same as:

$K=\frac{1}{2}m.v^{2}$

Now, if we double the kinetic energy, equation (2) changes to:

$2K=2\frac{p^{2}}{2m}$

$2K=\frac{p^{2}}{m}$ (3)

So, if we want to obtain the kinetic energy as shown in (3), the only option that works is increasing momentum by a factor of $\sqrt{2}$ or $2^{1/2}$ :

Applying this in (2):

$K=\frac{(\sqrt{2}p)^{2}}{2m}$

$K=\frac{(2p)^{2}}{2m}$

$K=\frac{p^{2}}{m}$ >>>As we can see, this equation is the same as equation (3)

Therefore, the correct answer is B

3 0

3 years ago

An artillery shell is fired with an initial velocity of 300 m/s at 55.0° above the horizontal. It explodes on a mountainside 42.

GuDViN [60]

Answer:

x=7227

y=1678

(7227,1678)

Explanation:

Ok, check the picture I attached you, because of the problem don't give us aditional information, let's asume that the projectile is fired from an initial position x=0 and y=0. Now let's use projectile motion equations, but firs let's find the initial velocity components in x-axis and y-axis:

$v_ox=v_o*cos(\theta_o)=300*cos(55)=172.0729309m/s$