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Free_Kalibri [48]
3 years ago
13

A boy is listening to the radio. The loudspeaker plays a musical note by vibrating 256 rimes esch second. How many times does th

e boys eardrum vibrate each second as he listens to the note?
Physics
1 answer:
Svet_ta [14]3 years ago
6 0

Answer:

 f_tympanum = 256 Hz.

Explanation:

The eardrum is the vibrating membrane of the human ear, it works by resonance, that is, an external stimulus (force) makes it vibrate, as the eardrum is extremely light it can vibrate at the same frequency of the incident sound.

Consequently if the incident vibration is f = 256 hz, the eardrum resonates at the same frequency

            f_tympanum = 256 Hz.

As a reference the response of the eardrum goes from f = 20 Hz f = 20000 Hz

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The Magnifying power of a telescope is M = 109.26

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Radius of curvature R = 5.9 m = 590 cm

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Focal length of eyepiece f_{eyepiece} = 2.7 cm

Magnifying power of a telescope is given by,

M = \frac{f_{objective} }{f_{eyepiece} }

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. A vertical electric field is set up in space to compensate for the gravitational force on a point charge. What is the required
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(a) The required magnitude of the electric field when the point charge is an electron is 5.57 x 10⁻¹¹ N/C.

(b) The required magnitude of the electric field when the point charge is an proton is 1.02 x 10⁻⁷ N/C.

<h3>Magnitude of electric field </h3>

The magnitude of electric field is given by the following equation.

F = qE

But F = mg

mg = qE

E = mg/q

where;

  • E is the electric field
  • m is mass of the particle
  • g is acceleration due to gravity
  • q is charge of the particle
<h3>For an electron</h3>

E = (9.11 x 10⁻³¹ x 9.8)/(1.602 x 10⁻¹⁹)

E = 5.57 x 10⁻¹¹ N/C

<h3>For proton</h3>

E = (1.67 x 10⁻²⁷ x 9.8)/(1.602 x 10⁻¹⁹)

E = 1.02 x 10⁻⁷ N/C

Thus, the required vertical electric field is greater when the charge is proton.

Learn more about electric field here: brainly.com/question/14372859

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2 years ago
A cord of mass 0.65 kg is stretched between two supports 8.0 m apart. If the tension in the cord is 120 N, how long will it take
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The time taken by the pulse to travel from one support to the other is 0.208 s.

<h3>Given:</h3>

The mass of the cord is m = 0.65 kg.

The distance between the supports is, d = 8.0 m.

The tension in the cord is T = 120 N.

The time taken by the pulse to travel from one support to the other is given as,

v=\frac{d}{t}

t=\frac{d}{v}

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v= 38.43 m/s

Then,

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