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WITCHER [35]
3 years ago
8

Hey! I need help with this question. Will give Brainlest!! Thanks in advance!

Physics
2 answers:
Evgesh-ka [11]3 years ago
8 0
The answers are In the book
yaroslaw [1]3 years ago
4 0
A) is Ep= mgh so since you already have mg which is 500N and h which is 10m multiply them and your answer will be 5000J potential energy.

b) do the same thing as a except use 5m instead of 10m which gives you 2500N

c) the potential energy is transferred to kinetic since he’s at bottom of hill of mechanical energy. so kinetic energy would be 5000J since that’s the mechanical energy since at top of hill there’s 0 kinetic, making all the potential the same as the mechanical
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A car accelerates uniformly from rest to 24.8 m/s in 7.88 s along a level stretch of road. Ignoring friction, determine the aver
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Answer:

When he weight of the car is 8.55 x 10^{3} N then power = 314.012 KW

When he weight of the car is 1.10 x 10^{4}  N then power =  43.76 KW

Explanation:

Given that

Initial velocity V_{1} = 0

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Time = 7.88 sec

We know that power required to accelerate the car is given by

P = \frac{change \ in \ kinetic \ energy}{time}

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Since Initial velocity V_{1} = 0

⇒ Δ K.E = \frac{1}{2} m V_{2}  ^{2}

⇒ Power P = \frac{1}{2} \frac{m}{t}  V_{2} ^{2}

⇒ Power P = \frac{1}{2} \frac{W}{g\ t}  V_{2} ^{2}   -------- (1)

(a). The weight of the car is 8.55 x 10^{3} N = 8550 N

Put all the values in above formula

So power P = \frac{1}{2} \frac{8550}{(9.81)\ (7.88)} (24.8) ^{2}

P = 314.012 KW

(b). The weight of the car is 1.10 x 10^{4} N = 11000 N

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P = \frac{1}{2} \frac{11000}{(9.81)\ (7.88)} (24.8) ^{2}

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stich3 [128]

Answer:

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