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Mkey [24]
3 years ago
12

A 150 kg uniform beam is attached to a vertical wall at one end and is supported by a cable at the other end. a) Calculate the m

agnitude of the vertical component of the force that the wall exerts on the left end of the beam if the angle between the cable and horizontal is θ = 47°.
Physics
1 answer:
Rus_ich [418]3 years ago
4 0

Answer:

1004.277N

Explanation:

Given that g = 9.817 ms^-2

If the angle between the cable and horizontal is 47°.

The angle between the cable and vertical is 90-47= 43°.

The weight of the beam is mg

The weight of the beam is

= 150*9.817

The weight of the beam is

= 1472.55N

magnitude of the vertical component of the force is mgsin(tita)

= 1472.55*sin43

= 1004.277N

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Answer:

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Explanation:

Given,

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The acceleration of the cart, a = 0.5 m/s²

The time interval of the cart, t = 30 s

The final velocity of the cart is given by the first equation of motion

                              v = u + at

                                  = 4 + (0.5 x 30)

                                = 19 m/s

Hence the final velocity of cart at 30 seconds is, v = 19 m/s

The speed of the cart at the end of  3 seconds

                                    V = 19 + (0.5 x 3)

                                       = 20.5 m/s

Hence, the final velocity of the cart at the end of this 3.0 second interval is, V = 20.5 m/s

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Answer:

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