Question

Plz help to solve it​

Answer 1

Step-by-step explanation:

X^(a²-b²+c²-a²+b²-c²) / X^(c(a-b)+b(c-a)+a(b-c))

= X^(0) / X^(ac-bc+bc-ab+ab-ac)

= X^0 / X^0

=1 / 1

= 1

Answer 2

Answer:

• 1

Step-by-step explanation:

• $(\frac{x^{a+b}}{x^c})^{a-b}*(\frac{x^{c+a}}{x^b})^{c-a}*(\frac{x^{b+c}}{x^a})^{b-c} =$
• $\frac{x^{a^2-b^2}}{x^{c(a-b)}}*\frac{x^{c^2-a^2}}{x^{b(c-a)}}*\frac{x^{b^2-c^2}}{x^{a(b-c)}} =$
• $\frac{x^{a^2-b^2+c^2-a^2+b^2-c^2}}{x^{c(a-b)+b(c-a)+a(b-c)}} =$
• $\frac{x^0}{x^0} =$
• 1