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3 years ago

Why we don’t feel atmospheric pressure?

Physics

2 answers:

Veseljchak [2.6K]3 years ago

8 0

Answer:

The reason we can't feel it is that the air within our bodies (in our lungs and stomachs, for example) is exerting the same pressure outwards, so there's no pressure difference and no need for us to exert any effort.

lesantik [10]3 years ago

4 0

Answer:We don't feel atmospheric pressure because the pressure in our bodies is almost the same as the atmospheric pressure outside

Explanation:

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At what time of year is the intensity of solar radiation striking each of earth's hemispheres weakest?

bagirrra123 [75]

During winter for a given hemisphere, solar radiation reaches the lowest period of its annual cycle due to the tilt of the earth on its axis. As the earth rotates around the sun, this tilt occludes a portion of the energy released by the sun as it diffuses in the atmosphere.

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3 years ago

An output gear has 10 teeth and an input gear has 40 teeth. What is the mechanical advantage of gear combination? Is force or sp

yKpoI14uk [10]

Answer:

Mechanical advantage: 4. Speed is multiplied

Explanation:

The mechanical advantage of gear combination is

$MA = \frac{N_i}{N_o}$

where

$N_i$ is the number of teeth in the input gear

$N_o$ is the number of teeth in the output gear

Here we have

$N_i = 40\\N_o = 10$

So we find

$MA = \frac{40}{10}=4$

In this example, it is the speed to be multiplied: the speed of the output gear is 4 times larger than the speed of the input gear. In fact, the mechanical advantage can be rewritten as

$MA= \frac{\omega_o}{\omega_i}$

where

$\omega_i$ is the angular speed of the input gear

$\omega_o$ is angular speed of the output gear

So re-arranging the equation, we find

$\omega_o = MA \cdot \omega_i = 4 \omega_i$

so, the speed of the output gear is 4 times larger than the speed of the input gear.

7 0

3 years ago

A car traveling at 28.0 m/s hits a bridge abutment. A passenger in the car, who has a mass of 49.0 kg, moves forward a distance

BaLLatris [955]

The final velocity of the passenger is zero as he is brought to rest by the inflated bag.

$V_f = 0$

Apply the equation of motion

$V_f^2 = V_i^2 +2as$

Replacing with our values,

$0 = 28^2+2(a)(0.55)$

$a = \frac{28^2}{2(0.55)}$

$a = 712.72m/s^2$

Calculate the force using the force equation,

$F = ma$

$F = (49kg)(712.72m/s^2)$

$F = 34.923kN$

Therefore the magnitude of force acts on the passenger's upper torso is 34.923kN

3 0

4 years ago

A body weighing 50 N is placed on a wooden table. How much force is required to set it into motion? Coefficient of friction betw

tigry1 [53]

If the coefficient of static friction is 0.3, then the minimum force required to get it moving is equal in magnitude to the maximum static friction that can hold the body in place.

By Newton's second law,

• the net vertical force is 0, since the body doesn't move up or down, and in particular

∑ F = n - mg = n - 50 N = 0 ==> n = 50 N

where n is the magnitude of the normal force; and

• the net horizontal force is also 0, since static friction keeps the body from moving, with

∑ F = F' - f = F' - µn = F' - 0.3 (50 N) = 0 ==> F' = 15 N

where F' is the magnitude of the applied force, f is the magnitude of static friction, and µ is the friction coefficient.

4 0

3 years ago

A piano string having a mass per unit length equal to 5.00× 10⁻³kg / m is under a tension of 1350N . Find the speed with which a

DiKsa [7]

Based on the mass per unit length and the tension, the speed that the wave travels on this string is 519.615 m/s.

<h3>What is the speed?</h3><h3 />

The speed that the wave travels can be found as:

Velocity² = Tension / Mass per length

Solving gives:

Velocity² = 1,350 / 0.005

Velocity² = 270,000

Velocity = √270,000

= 519.615 m/s

Find out more on the speed of a wave at brainly.com/question/12215474

#SPJ4

8 0

2 years ago