Ask question

Ask question

All categories

3 years ago

8

How are frequency and period related to each other? A. They are the same for any given wave B. They have the same magnitude but

opposite signs C. They are reciprocals of each other D. They are both found by squaring the amplitude of a wave

1 answer:

BabaBlast [244]3 years ago

3 0

Either of them is. 1/(the other one). That's 'C' .

You might be interested in

Linearly polarized light whose Jones vector is [0 1] (horizontally polarized) is sent through a train of two linear polarizers.

ivann1987 [24]

Answer:

Following are the solution to the given question:

Explanation:

The input linear polarisation was shown at an angle of $2 \mu$ . It's a very popular use of a half-wave plate. In particular, consider the case $\mu = 45 \pm$ , at which the angle of rotation is $90\pm$ . HWP thereby provides a great way to turn, for instance, a linear polarised light that swings horizontally to polarise vertically. Illustration of action on event circularly polarized light of the half-wave platform. Customarily it is the slow axis of HWP that corresponds to either the rotation. Note that perhaps the vector of polarization is "double-headed," i.e., the electromagnetic current swinging back and forward in time. Therefore the turning angle could be referred to as the rapid axis to reach the same result. Please find the attached file.

8 0

2 years ago

Using the formula F = M* A. What is the acceleration of a .5 kg

Katyanochek1 [597]

Answer:32 m/s/s

Explanation: since F=M*A, F=16N, M=0.5kg, A= F/M

A=16/0.5

A=32 m/s/s

7 0

2 years ago

Three masses are located in the x- y plane as follows: a mass of 6 kg is at (0 m, 0 m), a mass of 4 kg is at (3 m, 0 m), and a m

enot [183]

Answer:

The center of mass of three mass in the x-y plane is located at (1,0.5).

Explanation:

It is given that, a mass of 6 kg is at (0,0), a mass of 4 kg is at (3,0), and a mass of 2 kg is at (0,3). We need to find the center of mass of the system. Center of mass in x direction is :

$C_x=\dfrac{6\times 0+4\times 3+2\times 0}{6+4+2}\\\\C_x=1$

The center of mass in y direction is :

$C_y=\dfrac{6\times 0+4\times 0+2\times 3}{6+4+2}\\\\C_y=0.5$

So, the center of mass of three mass in the x-y plane is located at (1,0.5).

3 0

3 years ago

Q 19.23: A proton is initially moving at 3.0 x 105 m/s. It moves 3.5 m in the direction of a uniform electric field of magnitude

DENIUS [597]

Answer:

The kinetic energy of the proton at the end of the motion is 1.425 x 10⁻¹⁶ J.

Explanation:

Given;

initial velocity of proton, $v_p_i$ = 3 x 10⁵ m/s

distance moved by the proton, d = 3.5 m

electric field strength, E = 120 N/C

The kinetic energy of the proton at the end of the motion is calculated as follows.

Consider work-energy theorem;

W = ΔK.E

$W =K.E_f - K.E_i$

where;

K.Ef is the final kinetic energy

W is work done in moving the proton = F x d = (EQ) x d = EQd

$K.E_f =EQd + \frac{1}{2}m_pv_p_i^2$

$m_p \ is \ mass \ of \ proton = 1.673 \ \times \ 10^{-27} kg \\\\Q \ is \ charge \ of \ proton = 1.6 \times 10^{-19} C$

$K.E_f = 120\times 1.6 \times 10^{-19} \times 3.5 \ + \ \frac{1}{2}(1.673\times 10^{-27})(3\times 10^5)^2 \\\\$

$K.E_f = 6.72\times 10^{-17} \ + \ 7.53 \times 10^{-17} \\\\K.E_f = 14.25 \times 10^{-17} J\\\\K.E_f = 1.425\times 10^{-16} \ J$

Therefore, the kinetic energy of the proton at the end of the motion is 1.425 x 10⁻¹⁶ J.

3 0

3 years ago

A proton traveling with speed 2 × 105 m/s in the -y direction passes through a region in which there is a uniform magnetic field

stepladder [879]

Answer:

$\vec{E} = 1.2\times 10^5(-i)$

Explanation:

Given that

Speed ,v= 2 x 10⁵ m/s ( - y direction)

B= 0.6 T (- z direction)

The resultant force on the proton given as

$\vec{F}=q.\vec{E}+ q.(\vec{v}\times \vec{B})$

F= m a

For uniform motion acceleration should be zero.

F = 0

$0=q.\vec{E}+ q.(\vec{v}\times \vec{B})$

$0=\vec{E}+ (\vec{v}\times \vec{B})$

$0=\vec{E}+2\times 10^5(-j) \times 0.6(-k)$

$\vec{E} =- 2\times 10^5(-j) \times 0.6(-k)$

$\vec{E} =-1.2\times 10^5(i)$

$\vec{E} = 1.2\times 10^5(-i)$

Electric filed should be apply in the negative x direction.

5 0

2 years ago