Answer:
The induced current in the loop is 1.2 A
Explanation:
Given;
length of the wire, L = 24 cm = 0.24 m
resistance of the wire, R = 0.14 Ω.
magnetic field strength, B = 0.55 T
time, t = 15 ms = 15 x 10⁻³ s
Circumference of a circle is given as;
L = 2πr
0.24 = 2πr
r = 0.24 / 2π
r = 0.0382 m
Area of a loop is given as;
A = πr²
A = π (0.0382)²
A = 0.004585 m²
Induced emf is given as;
Ф = ΔB x A
Ф = ( 0 - 0.55 T) x 0.004585 m²
Ф = -0.002522 T.m²
According to ohm's law;
V = IR
Where;
I is current
The induced current in the loop is calculated as;
I = V / R
I = 0.168 / 0.14
I = 1.2 A
Therefore, the induced current in the loop is 1.2 A
The Ampere (A). You could literally google to be more efficient, all the same to me tho
The answer is Crest in transverse waves, this is where the particles are closest to each other due to the compression of the longitudinal component of the wave.
MA = Fwithout help/Fwith machine
MA = 1600/320 = 5
Velocity is computed using the formula:
Where:
V = speed
d = distance traveled
t = time/period
First you need to consider that the orbit is circular. To get the measurement or the distance going around Earth, you will need to get the circumference of the path.
Where:
C = circumference
π = 3.14
r = radius
The Earth has a radius of 6,400km, but you also need to consider that the satellite is orbiting above the surface of the Earth, so you add in the 2,000km to that radius.
r = 6,400Km + 2,000Km =
8,400Km
Next step is to insert that into our circumference formula:
The distance traveled would then be
52,778.76KmNow that we have the distance, we can then get the velocity:
The speed of the satellite is
4,398.23km/hr.
