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lutik1710 [3]
3 years ago
15

Two lab partners, Mary and Paul, are both farsighted. Mary has a near point of 68.6 cm from her eyes and Paul has a near point o

f 128 cm from his eyes. Both students wear glasses that correct their vision to a normal near point of 25.0 cm from their eyes, and both wear glasses 1.80 cm from their eyes. In the process of wrapping up their lab work and leaving for their next class, they exchange glasses (Mary leaves with Paul's glasses and Paul leaves with Mary's glasses). When they get to their next class, find the following.
(a) Determine the distance to the closest object that Mary can see clearly (relative to her eyes) while wearing Paul's glasses.
(b) Determine the distance to the closest object that Paul can see clearly (relative to his eyes) while wearing Mary's glasses.
Physics
1 answer:
Misha Larkins [42]3 years ago
8 0

Answer:

a) 27.7 cm  

b) 19.9 cm

Explanation:

for mary  

d1i = 68.6-1.8 = 66.8 cm

d1o = 25-1.8 = 23.2 cm

1/f1 = 1/d1o + 1/d1i

1/f1 = -(1/23.2)-(1/66.8)

f1 = -17.22 cm

for paul

d2o = 25-1.8 = 23.2 cm

d2i = 128-1.8 = 126.2 cm

1/f2= 1/d2o + 1/d2i

1/f2 = -(1/23.2)-(1/126.2)

f2 = -19.6 cm

a)

1/do + 1/d1i = 1/f2

1/do - (1/66.8) = -1/19.6

do = 27.7 cm  

part b)

1/do + 1/d2i = 1/f1

1/do - (1/126.2) = -(1/17.22)

do = 19.9 cm

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Average Velocity = Total Displacement / Total time

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Average Velocity = Total Displacement / Total time

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Option C. 
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3 years ago
A uniform marble rolls down a symmetrical bowl, start- ing from rest at the top of the left side. The top of each side is a dist
Paha777 [63]

Answer:

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Part b)

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Part c)

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As we know by energy conservation the total energy at the bottom of the bowl is given as

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here we know that on the left side the ball is rolling due to which it is having rotational and transnational both kinetic energy

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so the height on the smooth side is given as

h' = \frac{10}{14} h

Part b)

if both sides are rough then it will reach the same height on the other side because the energy is being conserved.

Part c)

Since marble will go to same height when it is rough while when it is smooth then it will go to the height

h' = \frac{10}{14} h

so on smooth it will go to lower height

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3 years ago
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Answer:

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<h2>Answer: electrostatic and gravitational force </h2><h2 />

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