3 years ago

A car travels a distance of 400 m in 5 seconds. Calculate its average velocity.

Physics

2 answers:

Vlada [557]3 years ago

8 0

Total distance=400m

Total time=5s

$\boxed{\sf Average\:Velocity=\dfrac{Total \:Distance}{Total\:Time}}$

$\\ \sf\longmapsto Average\:Velocity=\dfrac{400}{5}$

$\\ \sf\longmapsto Average\:Velocity=80m/s$

ikadub [295]3 years ago

5 0

Answer:

80 m/s

Explanation:

x = 400 m

t = 5 s

x = vt,

400 = v(5),

80 = v

You might be interested in

A toy cart is pulled a distance of 6.00 m in a straight line across the floor. The force pulling the cart has a magnitude of 20.

aivan3 [116]

Answer:

W = 95.8J

Explanation:

Given

S = 6.00m

F =20.0N

Theta = 37°

W = FSCos(theta)

W = 20×6.0×Cos(37)

W = 95.8J

8 0

3 years ago

Read 2 more answers

A flap of tissue that prevents blood from flowing back is a(n)________ .

ioda

A valve is a flap of tissue that prevents blood from flowing back

6 0

3 years ago

Two high-current transmission lines carry currents of 29.0 A and 78.0 A in the same direction and are suspended parallel to each

jarptica [38.1K]

Answer with Explanation:

We are given that

$I_1=29 A$

$I_2=78 A$

$d=38 cm=\frac{38}{100}=0.38 m$

$1 m=100 cm$

a.Length of segment,l=20 m

Magnetic force ,F= $\frac{2\mu_0I_1I_2 l}{4\pi d}$

$\frac{\mu_0}{4\pi}=10^{-7}$

Substitute the values

$F=\frac{10^{-7}\times 29\times 78\times 20}{0.38}=0.0119 N$

Hence, the magnetic force exert by each segment on the other=0.0119 N

b.We know that when current carrying in the wires are in same direction then the force will attract to each other.

Hence, the force will be attractive.

4 0

3 years ago

Read 2 more answers

The mineral quartz has a chemical formula of SiO2. What is the formal name<br> for this compound?

lana66690 [7]

Answer:

Silicon Dioxide

3 0

2 years ago

Read 2 more answers

a projectile is launched at an angle of 30 degrees and lands later at the same level. if it's initial speed is 50 m/s, solve for

Mrrafil [7]

$using \: the \: formula \\ t = \frac{2u \sin( \alpha ) }{g} where \: u = initial \: speed \: \\ \alpha = angle \: of \: projection \\ g = acceleration \: due \: to \: gravity \\ \frac{2 \times 50 \times \sin(30) }{10} \\ \frac{100 \times 0.5}{10} = \frac{50}{10} = 5seconds$

Maximum height
= (Usinα)^2/2g
(50*0.5)^2/20
25^2/20
625/20
=31.25metres
horizontal distance = Range= [U^2 * sin2α]/g
[50^2 * sin60]/10
2500 * 0.8660/10
2165/10=216.5metres

3 0

3 years ago