120 minutes=2 hours
20/2= 10mph
The force exerted by the laser beam on a completely absorbing target is
.
The given parameters;
- <em>power of the laser light, P = 1050 W</em>
- <em>wavelength of the emitted light, λ = 10 μm </em>
The speed of the emitted laser light is given as;
v = 3 x 10⁸ m/s
The force exerted by the laser beam on a completely absorbing target is calculated as follows;
P = Fv

Thus, the force exerted by the laser beam on a completely absorbing target is
.
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Answer:
D
Explanation:
Because we have two reactants and product
Answer:
8.854 pF
Explanation:
side of plate = 0.1 m ,
d = 1 cm = 0.01 m,
V = 5 kV = 5000 V
V' = 1 kV = 1000 V
Let K be the dielectric constant.
So, V' = V / K
K = V / V' = 5000 / 1000 = 5
C = ε0 A / d = 8.854 x 10^-12 x 0.1 x 0.1 / 0.01 = 8.854 x 10^-12 F
C = 8.854 pF