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Mrrafil [7]
3 years ago
14

A toy cart is pulled a distance of 6.00 m in a straight line across the floor. The force pulling the cart has a magnitude of 20.

0 N and is directed at 37° above the horizontal. What is the work done by this force?

Physics
2 answers:
aivan3 [116]3 years ago
8 0

Answer:

W = 95.8J

Explanation:

Given

S = 6.00m

F =20.0N

Theta = 37°

W = FSCos(theta)

W = 20×6.0×Cos(37)

W = 95.8J

Novosadov [1.4K]3 years ago
6 0

Given Information:  

Horizontal distance = d = 6.0 m  

Force = F = 20 N

Angle = θ = 37°

Required Information:  

Work done = W = ?

Answer:  

Work done = 95.84 Joules

Explanation:  

The work done on toy cart is given by

W = Fdcos(θ)

Where F is the force applied, d is the distance by which the toy cart has been displaced, and θ is the angle between F and horizontal floor.  

As you can see in the attached diagram, The force pulling the cart makes an angle of 37 with respect to the horizontal surface.

W = 20*6*cos(37°)

W = 95.84 Joules

Therefore, 95.84 Joules of work has been by a force of 20 N to displace the toy cart by 6 meters.

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Answer:

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Tranform the units

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1. A pendulum has a period of 3 seconds. What's its frequency? 2. A pendulum has a frequency of 0.25 Hz. What's its period? 3. A
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Answer:

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(3) 2 sec, 0.5 Hz

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(1) We have given time period of pendulum is 3 sec

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svlad2 [7]

Answer:

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Explanation:

The student wants to prove hooke's law which has the form

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To do this we hang the spring in a vertical position and mark the equilibrium position on a tape measure, to simplify the calculations we can make this point zero by placing our reference system in this position.

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