A toy cart is pulled a distance of 6.00 m in a straight line across the floor. The force pulling the cart has a magnitude of 20.
0 N and is directed at 37° above the horizontal. What is the work done by this force?
2 answers:
Given Information:
Horizontal distance = d = 6.0 m
Force = F = 20 N
Angle = θ = 37°
Required Information:
Work done = W = ?
Answer:
Work done = 95.84 Joules
Explanation:
The work done on toy cart is given by
W = Fdcos(θ)
Where F is the force applied, d is the distance by which the toy cart has been displaced, and θ is the angle between F and horizontal floor.
As you can see in the attached diagram, The force pulling the cart makes an angle of 37 with respect to the horizontal surface.
W = 20*6*cos(37°)
W = 95.84 Joules
Therefore, 95.84 Joules of work has been by a force of 20 N to displace the toy cart by 6 meters.
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