Question

A toy cart is pulled a distance of 6.00 m in a straight line across the floor. The force pulling the cart has a magnitude of 20.0 N and is directed at 37° above the horizontal. What is the work done by this force?

Answer 1

Answer:

W = 95.8J

Explanation:

Given

S = 6.00m

F =20.0N

Theta = 37°

W = FSCos(theta)

W = 20×6.0×Cos(37)

W = 95.8J

Answer 2

Given Information:  

Horizontal distance = d = 6.0 m  

Force = F = 20 N

Angle = θ = 37°

Required Information:  

Work done = W = ?

Answer:  

Work done = 95.84 Joules

Explanation:  

The work done on toy cart is given by

W = Fdcos(θ)

Where F is the force applied, d is the distance by which the toy cart has been displaced, and θ is the angle between F and horizontal floor.  

As you can see in the attached diagram, The force pulling the cart makes an angle of 37 with respect to the horizontal surface.

W = 20*6*cos(37°)

W = 95.84 Joules

Therefore, 95.84 Joules of work has been by a force of 20 N to displace the toy cart by 6 meters.