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Mrrafil [7]
3 years ago
14

A toy cart is pulled a distance of 6.00 m in a straight line across the floor. The force pulling the cart has a magnitude of 20.

0 N and is directed at 37° above the horizontal. What is the work done by this force?

Physics
2 answers:
aivan3 [116]3 years ago
8 0

Answer:

W = 95.8J

Explanation:

Given

S = 6.00m

F =20.0N

Theta = 37°

W = FSCos(theta)

W = 20×6.0×Cos(37)

W = 95.8J

Novosadov [1.4K]3 years ago
6 0

Given Information:  

Horizontal distance = d = 6.0 m  

Force = F = 20 N

Angle = θ = 37°

Required Information:  

Work done = W = ?

Answer:  

Work done = 95.84 Joules

Explanation:  

The work done on toy cart is given by

W = Fdcos(θ)

Where F is the force applied, d is the distance by which the toy cart has been displaced, and θ is the angle between F and horizontal floor.  

As you can see in the attached diagram, The force pulling the cart makes an angle of 37 with respect to the horizontal surface.

W = 20*6*cos(37°)

W = 95.84 Joules

Therefore, 95.84 Joules of work has been by a force of 20 N to displace the toy cart by 6 meters.

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A rock is suspended from a string, and it accelerates downward. Which one of the following statements is correct? Group of answe
Tems11 [23]

Answer:

a. The magnitude of the tension in the string is greater than the magnitude of the weight of the rock.

Explanation:

During the motion of the rock while it is in downward motion we can say

T - mg cos\theta = ma_c

since it is performing circular motion so we will have its acceleration towards its center

T = mgcos\theta + ma_c

a_c = \frac{v^2}{L}

T = mgcos\theta + \frac{mv^2}{L}

So at the lowest point of the path we can say

T = mg + \frac{mv^2}{L}

so correct answer is

a. The magnitude of the tension in the string is greater than the magnitude of the weight of the rock.

4 0
3 years ago
A student pulls a box across a horizontal floor at a constant speed of 4.0 meters per second by exerting a constant horizontal f
ruslelena [56]
Work = Force multiplied by the distance(or displacement)
8 0
3 years ago
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Rank the six combinations of electric charges on the basis of the electric force acting on q1. Define forces pointing to the rig
g100num [7]

I have attached the image showing the 6 combination of charges

Answer:

Smallest are: q1 = +1 nc, q2 = +1 nc, q3 = +1 nc and q1 = -1 nc, q2 = -1 nc, q3 = -1nc

Third Largest: q1 = +1 nc, q2 = +1nc, q3 = -1 nc

Second Largest: q1 = +1 nc, q2 = -1 nc, q3 = +1 nc

Largest are: q1 = +1 nc, q2 = -1 nc, q3 = -1 nc and q1 = -1 nc, q2 = +1 nc, q3 = +1 nc

Explanation:

The electrostatic force between 2 charges is; F = k•q1•q2/r²

Where r is the distance between the 2 charges q1 and q2 and k is coulombs constant.

Thus;

F ∝ q1•q2/r²

The net force on the charge q1 is the sum of the forces on charge q2 and q3.

If the two charges are opposite, the force is an attractive force while if the two charges are similar, the force is a repulsive force.

Thus, if the combination has same type of charges, i.e;(+1,+1,+1) or (-1,-1,-1), the force will be very small.

So, now the order of forces from smallest to largest is;

Smallest are: q1 = +1 nc, q2 = +1 nc, q3 = +1 nc and q1 = -1 nc, q2 = -1 nc, q3 = -1nc

Third Largest: q1 = +1 nc, q2 = +1nc, q3 = -1 nc

Second Largest: q1 = +1 nc, q2 = -1 nc, q3 = +1 nc

Largest are: q1 = +1 nc, q2 = -1 nc, q3 = -1 nc and q1 = -1 nc, q2 = +1 nc, q3 = +1 nc

3 0
3 years ago
PL-1) A spring that hangs vertically is 25 cm long when no weight is attached to its lower end. Steve adds 250 g of mass to the
Anuta_ua [19.1K]

Answer:

20.42 N/m

Explanation:

From hook's law,

F = ke ......................... Equation 1

Where F = Force applied to the spring., k = spring constant, e = extension.

Make k the subject of the equation,

k = F/e ................. Equation 2

Note: The force on the spring is equal to the weight of the mass hung on it.

F = W = mg.

k = mg/e................ Equation 3

Given: m = 250 g = 0.25 kg, e = 37-25 = 12 cm = 0.12 m.

Constant: g = 9.8 m/s²

Substitute into equation 3

k = (0.25×9.8)/0.12

k = 20.42 N/m.

Hence the spring constant = 20.42 N/m

7 0
3 years ago
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Makovka662 [10]
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5 0
3 years ago
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