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Alex73 [517]
3 years ago
15

What is the velocity of a group of explorers traveling from Antarctica to Australia, traveling 1500 miles in 48 hours?31.25 mph

south
72,000 mph
48 mph
31.3 mph north
Physics
1 answer:
Brums [2.3K]3 years ago
7 0

Answer:

31.3mph North

Explanation:

Given parameters:

Distance traveled  = 1500miles

Time taken  = 48hrs

Unknown:

Velocity of the group of explorers = ?

Solution:

Velocity is the displacement divided by the time taken. It is a vector quantity with both magnitude and direction.

 So;

       Velocity = \frac{displacement}{time}

Displacement is the distance moved in a specific direction = 1500miles North

 Insert the parameters and solve;

   Velocity = \frac{1500}{48}   = 31.3mph North

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Answer:

\theta = 76.9 degree

Explanation:

As we know that the resultant of two vectors is given as

R = \sqrt{F_1^2 + F_2^2 + 2F_1 F_2 cos\theta

here we know that

R = 87 Lb

F_1 = 41 Lb

F_2 = 68 Lb

now we have

87 = \sqrt{41^2 + 68^2 + 2(41)(68)cos\theta

87^2 = 6305 + 5576 cos\theta

\theta = cos^{-1}(\frac{1264}{5576})

\theta = 76.9 degree

7 0
3 years ago
What temperature resistivity of tungsten is 4 times resistivity of silver?
mihalych1998 [28]

Answer:

Slightly above 20°c

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The resistivity of tungsten at 20°c is 5.6x10-8Ωm

We see the value is just an approximation of 4 times not exactly.

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A longitudinal wave is a combination of a transverse wave and a surface wave.(true or false)
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Car moves 5km East,3km south,2km West, 1km north find displacement<br>(please show me the way)​
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Read 2 more answers
What magnification will be produced by a lens of power –4.00 D (such as might be used to correct myopia) if an object is held 43
kiruha [24]

Answer:

The magnification is m  = 0.3674

Explanation:

From the question we are told that

  The  power of the lens is  P = -4.00 D(dioptre)

Generally  1 dioptre = 1 \ meter

  The object distance is u =  -43 \ cm the negative sign is because the distance is measured in the opposite direction of incident light (i.e away )

 Generally the focal length is mathematically represented as

          f = \frac{1}{P}  

   =>f = \frac{1}{4.00 }  

  =>  f = 0.25 \ m

converting to  cm  

 =>   f = 0.25 \ m = 0.25 * 100 = 25 \ cm

Generally from lens equation  we have that  

     \frac{1}{f} +\frac{1}{v} -\frac{1}{u}

=>  \frac{1}{25} +\frac{1}{v} -\frac{1}{-43}

=>   v =  -15.8 \ cm

Generally the magnification is mathematically represented as

      m  = \frac{v}{u}

=>    m  = \frac{- 15.8}{-43}

=>    m  = 0.3674

6 0
3 years ago
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