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Alex73 [517]
3 years ago
15

What is the velocity of a group of explorers traveling from Antarctica to Australia, traveling 1500 miles in 48 hours?31.25 mph

south
72,000 mph
48 mph
31.3 mph north
Physics
1 answer:
Brums [2.3K]3 years ago
7 0

Answer:

31.3mph North

Explanation:

Given parameters:

Distance traveled  = 1500miles

Time taken  = 48hrs

Unknown:

Velocity of the group of explorers = ?

Solution:

Velocity is the displacement divided by the time taken. It is a vector quantity with both magnitude and direction.

 So;

       Velocity = \frac{displacement}{time}

Displacement is the distance moved in a specific direction = 1500miles North

 Insert the parameters and solve;

   Velocity = \frac{1500}{48}   = 31.3mph North

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Unpolarized light with an intensity of 22.4 ????ux passes through a polarizer whose transmission axis is vertically oriented. (a
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Answer:

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Explanation:

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consequently the above the processed light has half of the incident intensity and the directional of the polarized

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b) The polarized light falls on a second polarizer, therefore it must comply with the law of Malus

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In a 350-m race, runner A starts from rest and accelerates at 1.6 m/s^2 for the first 30 m and then runs at constant speed. Runn
kifflom [539]

Answer:

B can take 0.64 sec for the longest nap .

Explanation:

Given that,

Total distance = 350 m

Acceleration of A = 1.6 m/s²

Distance = 30 m

Acceleration of B = 2.0 m/s²

We need to calculate the time for A

Using equation of motion

s=ut+\dfrac{1}{2}at_{A}^2

Put the value in the equation

30=0+\dfrac{1}{2}\times1.6\times t_{A}^2

t_{A}=\sqrt{\dfrac{30\times2}{1.6}}

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We need to calculate the time for B

Using equation of motion

s=ut+\dfrac{1}{2}at_{B}^2

Put the value in the equation

30=0+\dfrac{1}{2}\times2.0\times t_{B}^2

t_{B}=\sqrt{\dfrac{30\times2}{2.0}}

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We need to calculate the time for longest nap

Using formula for difference of time

t'=t_{A}-t_{B}

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Hence, B can take 0.64 sec for the longest nap .

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