Answer:
36.29 m/s
Explanation:
We know from theory that
. Let's replace the value we know in our equation and solve for the only value left.

The mass of the planet Gallifrey is 8 times the mass of the Earth.
- let the gravitational field of Earth = g
- let the radius of the Earth = R
- gravitational field of Gallifrey = 2g
- radius of Gallifrey = 2R
<h3>What is gravitational potential energy?</h3>
- This is the work done in moving an object to a certain distance against gravitational field.
The gravitational field strength of the Earth is given as follows;

The gravitational field strength of the Planet Gallifrey is calculated as follows;


Thus, the mass of the planet Gallifrey is 8 times the mass of the Earth.
Learn more about gravitational field strength here: brainly.com/question/14080810
Answer:
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<h2>Answer</h2>
Option A that is 8.8 × 10^3 m/s
<h2>Explanation</h2>
The magnetic field B is defined from the Lorentz Force Law, and specifically from the magnetic force on a moving charge. It says
Field-strength = BVqsinΔ
<h2>v = E/B </h2>
Since field are perpendicular so sin90 = 1
v = 4.6/10^4 / 5.2
v = 8846.15 m /s
The speed at which electrons pass through the selector without deflection = 8846.15 m /s
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