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PtichkaEL [24]
3 years ago
7

Please do not answer if you don’t now the answer

Mathematics
1 answer:
Rainbow [258]3 years ago
4 0

Answer:

R___S___T

RT=RS+ST

39 = (23 - 2x) + (9x - 5)

39 =7x + 18

7x = 39 - 18

7x = 26

x = 26/7

x= 3.7

RS= 23 - 2x = 23 - 2(3.7) = 23 - 7.4 = 15.6

If went ST = 9x -5 = 9(3.7)- 5 = 33.3 - 5 = 28.3

I hope I helped you^_^

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Leona [35]

Answer:

8m^2n^3, 4n-5m, and 4n+5m

Step-by-step explanation:

128m^2n^5-200m^4n^3 <-- Given

m^2(128n^5-200m^2n^3) <-- Factor out m²

m^2n^3(128n^2-200m^2) <-- Factor out n³

8m^2n^3(16n^2-25m^2) <-- Factor out 8

8m^2n^3(4n-5m)(4n+5m) <-- Difference of Squares

Therefore, the factors are 8m^2n^3, 4n-5m, and 4n+5m

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3 years ago
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stellarik [79]

Answer:

x = 4

Step-by-step explanation:

180 = 102 + 24x - 18

  1. 102 - 18 = 84
  2. subtract 84 from both sides
  3. 96 = 24x
  4. divide both sides by 4
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Please answer question from photo
Radda [10]
We are given the equation of a line

y = -2x + 1

We have to find the value of y at three different values of x i.e. at x =0, -3 and 1

In order to find the value of y at any given x, simply replace x by that number.

So, for x=0, we will replace x by 0 to find the value of y. So y will be:
y = -2(0) + 1
y = 1
This can be expressed as an ordered pair as (0,1)

Similarly for x=-3, we get:
y = -2(-3) + 1 = 6 + 1
y = 7
This can be expressed as an ordered pair as (-3, 7)

And, finally for x=1, we get:
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This can be expressed as an ordered pair as (-1, -1)
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Line ℓ1 has the equation y=x–5 and line ℓ2 has the equation y=x–1. Find the distance between ℓ1 and ℓ2. round your answer to the
Rus_ich [418]

\ell_1 and \ell_2 are parallel to one another with slope 1. Any line with slope -1 is perpendicular to both of these lines, the simplest being y=-x.

This perpendicular line intersects \ell_1 and \ell_2 at the points (5/2, -5/2) and (1/2, -1/2), respectively.

The distance between \ell_1 and \ell_2 is the same as the distance between these two intersections:

\sqrt{\left(\dfrac52-\dfrac12\right)^2+\left(-\dfrac52+\dfrac12\right)^2}=2\sqrt2\approx\boxed{2.8}

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3 years ago
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nirvana33 [79]

Answer:

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Step-by-step explanation:

Put the minus signs where the problem statement tells you. As with any function, the argument replaces the variable in the function definition. That is, for g(-x), you put (-x) where x is in the definition of the function.

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  -g(x) = -(70 -3x) = -70 +3x

  -g(-x) = -(70 -3(-x)) = -70 -3x

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