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3 years ago

What is the volume of the right rectangular prism?

Mathematics

1 answer:

ddd [48]3 years ago

5 0

Answer:

i think its 735

Step-by-step explanation:

since the base is a square it should be a whole square which is 7 and the height is 15 and v=whl and multiply all of it 7 times 7 is 49 times 15 is 735.

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Write the first five terms of the sequence defined by the explicit formula

denis-greek [22]

Answer:

The correct answer option is: 19, 13, 3, -11, -29.

Step-by-step explanation:

We are given the following explicit formula for an arithmetic sequence:

$a_n=21-2n^2$

So to find the first five terms of this sequence, we will substitute the values of $n$ (num here in the given formula:

$a_1=21-2(1)^2\\\\a_1=19$

$a_2=21-2(2)^2\\\\a_2=13$

$a_3=21-2(3)^2\\\\a_3=3$

$a_4=21-2(4)^2\\\\a_4=-11$

$a_5=21-2(5)^2\\\\a_5=-29$

Therefore, the first five terms of the sequence defined by the explicit formula $a_n=21-2n^2$ are 19, 13, 3, -11, -29.

5 0

3 years ago

Read 2 more answers

Identify the reference angle

ser-zykov [4K]

Answer:

Below in bold.

Step-by-step explanation:

300 degrees - reference angle is |360 - 300 |= 60 degrees

225 = 225 - 180 = 45 degrees

480 = 480 - 360 = 120 so it is 180 - 120 = 60 degrees.

-210 = |-210 + 180| = 30 degrees.

7 0

3 years ago

Step 3: Solving a system of equations to make comparisons between men and women

zysi [14]

I am also not able to solve thi s question

7 0

3 years ago

The sprocket on the crankshaft of an engine power the camshaft by a chain assembly. If the engine crankshaft is turning 3250 rev

Lera25 [3.4K]

Answer:

30,631 inches
2553 feet

Step-by-step explanation:

The length of one revolution of the sprocket is ...

C = 2πr = 2π(1.5 in) = 3π in

Then the length of 3250 revolutions is ...

3250(3π in) = 30,630.53 in

About 30,631 inches of chain travel past the sprocket in one minute.

There are 12 inches in a foot, so the number of feet is ...

30,630.53 in/(12 in/ft) = 2552.54 ft

About 2553 feet of chain travel past in one minute.

8 0

4 years ago

C. Line m is a perpendicular bisector. If EG=12 and FG=5, of then how long is:

strojnjashka [21]

Answer:

$EF = 13$

$GH = 5$

$EH = 13$

Step-by-step explanation:

Given

The attached figure

$EG = 12$

$FG = 5$

Solving (a): EF

Since m is a perpendicular bisector, then <EGF and <EGH are right-angled.

So, EF will be calculated using Pythagoras theorem which states:

$EF^2 = EG^2 + FG^2$

$EF^2 = 12^2 + 5^2$

$EF^2 = 144 + 25$

$EF^2 = 169$

Take the positive square roots of both sides

$EF = \sqrt{169$

$EF = 13$

Solving (b): GH

Since m is a perpendicular bisector, then GH = FG

$FG = 5$

$GH = FG$

$GH = 5$

Solving (c): EH

Since m is a perpendicular bisector, then EH = EF

$EF = 13$

$EH = EF$

$EH = 13$

4 0

3 years ago