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3 years ago

Write the number below in scientific notation rounded off to 3 significant figures.

Chemistry

1 answer:

pychu [463]3 years ago

4 0

Answer:

0.000110

Explanation:

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Lakesha gave three tenths of her cookies to Bailey and five tenths of her cookies to Helen. What fraction of her cookies did Lak

Mashutka [201]

Answer:

a . eight tenths of her cookies

Explanation:

Let the total number of Lakesha's cookies be represented by x.

So that;

She gave three tenths to Bailey = $\frac{3}{10}$ of x

= $\frac{3x}{10}$

She gave five tenths to Helen = $\frac{5}{10}$ of x

= $\frac{5x}{10}$

Fraction of Lakesha's cookies given away = $\frac{3x}{10}$ + $\frac{5x}{10}$

= $\frac{3x+ 5x}{10}$

= $\frac{8x}{10}$

Thus, the fraction of cookies given away by Lakesha is $\frac{8}{10}$ .

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3 years ago

In which grouping of the periodic table do the elements have simliar properties

STatiana [176]

I would have to say [c]

but it could also be [b]

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3 years ago

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9- Which pair of formulae represents two alkanes? (1 mark)

Ksenya-84 [330]

Answer:

A) CH4 and C8H18

Explanation:

General Formula for an Alkane = CnH2n+2

This means for every number of Carbon (C) atoms, there are twice as many Hydrogen (H) atoms with an additional two added onto that.

Therefore, if there is one Carbon Atom, and we multiply that by two, and then add an additional two, we get 4 Hydrogen atoms, so CH4, which is our first Formulae

Secondly, if we have eight Carbon Atoms, and we multiple that by two (16), and then add an additional two, we get 18 Hydrogen atoms, so C8H18, which is our second Formulae

The other Formulas do not follow this 'General Formula'

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2 years ago

PLSS HELP! The gas carbon dioxide is a pure substance. Which of the following is true about carbon dioxide? (4 points)

Nadusha1986 [10]

Answer:

The answer is option A..

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3 years ago

What is the temperature change in 355 mL of water upon absorption of 34 kJ of heat? (The specific heat capacity of water is 4.18

frozen [14]

The temperature change is 23 °C.

q = mCΔT

ΔT = q/(mC)

m = 355 g

∴ ΔT = (34 000 J)/(355 g × 4.184 J·°C⁻¹g⁻¹) = 23 °C

Note: The answer can have only two significant figures because that is all you gave for the amount of heat absorbed.

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3 years ago

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