Answer:
F = 520 N
Explanation:
For this exercise the rotational equilibrium equation should be used
Σ τ = 0
Let's set a reference system with the origin at the back of the refrigerator and the counterclockwise rotation as positive. On the x-axis it is horizontal directed outward, eg the horizontal y-axis directed to the side and the z-axis vertical
Torque is
τ = F x r
the bold indicate vectors, we analyze each force
the applied force is horizontal along the -x axis, the arm (perpendicular distance) is directed in the z axis,
The weight of the body is the vertical direction of the z-axis, so the arm is on the x-axis
-F z + W x = 0
F z = W x
F =
W
The exercise indicates the point of application of the force z = 1.5 m and the weight is placed in the center of mass of the body x = 0.6 m, we are assuming that the force is applied in the wide center of the refrigerator
let's calculate
F = 1300 0.6 / 1.5
F = 520 N
Wonderful.
You've given us ' m '.
Now, if we only had ' a ', we could come back at you with ' f '.
Answer:
100N
Explanation:
because newton's third law of motion states that if body A exerts a force on the body B, then Body B will exert an equal force but opposite in direction force on body A
so if the fly experienced 100N, then the car will also experience 100N
hope you get it
please mark
Answer:
The initial and final temperatures of the gas is 300 K and 600 K.
Explanation:
Given that,
Entropy of the gas = 14.41 J/K
Absorb gas = 6236 J
We know that,

At constant pressure,



Put the value into the formula




...(I)
We need to calculate the initial and final temperatures of the gas
Using formula of energy

Put the value into the formula




Put the value of T₂


Put the value of T₁ in equation (I)


Hence, The initial and final temperatures of the gas is 300 K and 600 K.
Answer:
2069.76 N
Explanation:
density of wood = 824 kg/m^3
density of water = 1000 kg/m^3
Volume of wood = 1.2 m^3
True weight of wood = volume of wood x density of wood x gravity
True weight of wood = 1.2 x 824 x 9.8 = 9690.24 N
Buoyant force acting on wood = volume of wood x density of water x gravity
Buoyant force acting on wood = 1.2 x 1000 x 9.8 = 11760 N
Tension in the rope = Buoyant force - True weight
tension in rope = 11760 - 9690.24 = 2069.76 N