Answer:
-0.4454 Joules
Explanation:
m = Mass of block = 2 kg
h = Height of extension = 17 cm = x
g = Acceleration due to gravity = 9.81 m/s²
Potential energy of the spring

The kinetic energy of the spring

In this system as the potential and kinetic energy is conserved from work energy equivalence we get

The work done by friction is -0.4454 Joules
Mechanical and electrical
<u>Answer:</u> The weight of the object is 29.4 N
<u>Explanation:</u>
To calculate the weight of the object, we use the equation:

where,
m = mass of the object = 3 kg
g = acceleration due to gravity = 
Putting values in above equation, we get:

Hence, the weight of the object is 29.4 N
Answer:
<u>
</u>
Explanation:
Normal reaction from 40 kg slab on 10 kg block
M × g = 10 × 9.8 = 98 N
Static frictional force = 98 × 0.7 N
Static frictional force = 68.6 N is less than 100 N applied
10 kg block will slide on 40 kg slab and net force on it
= 100 N - kinetic friction

= 100 - 39.2
= 60.8 N




Frictional force on 40 kg slab by 10 kg block = 98 × 0.4
Frictional force on 40 kg slab by 10 kg block = 39.2 N


40 kg slab will move with = 
