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MaRussiya [10]
3 years ago
15

Is water a mixture or substance​

Physics
2 answers:
elena55 [62]3 years ago
7 0

Hey!

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Answer:

Substance

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Explanation:

Water is a substance created with oxygen and hydrogen.

A mixture is when more than one substance are mixed together.

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Hope This Helped! Good Luck!

NARA [144]3 years ago
6 0

Answer:sub

Explanation:

A mixture is when two or more substances combine physically together.

However, in water, two hydrogen atoms combine with one oxygen atom chemically, forming a new substance that has properties different from hydrogen alone or oxygen alone.

For example, if you combine iron powder and sulfur powder physically (just mixing them together without applying heat), you can find that the mixture retains the properties of the original components, i.e. you can still use a magnet to attract the iron inside the mixture.

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A massless spring with force constant ????=200N/m hangs from the ceiling. A 2.0-kg block is attached to the free end of the spri
Makovka662 [10]

Answer:

-0.4454 Joules

Explanation:

m = Mass of block = 2 kg

h = Height of extension = 17 cm = x

g = Acceleration due to gravity = 9.81 m/s²

Potential energy of the spring

P=mgh\\\Rightarrow P=2\times 9.81\times 0.17\\\Rightarrow P=3.3354\ J

The kinetic energy of the spring

K=\frac{1}{2}mx^2\\\Rightarrow K=\frac{1}{2}\times 200\times 0.17^2\\\Rightarrow K=2.89\ J

In this system as the potential and kinetic energy is conserved from work energy equivalence we get

W=P-K\\\Rightarrow W=2.89-3.3354\\\Rightarrow W=-0.4454\ J

The work done by friction is -0.4454 Joules

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3 years ago
What happens to the size of the image as the focal length is increased?
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What two energies does a bulldozer use​
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3 years ago
For an object with a given mass on Earth, calculate the weight of the object with the mass equal in magnitude to the number repr
leonid [27]

<u>Answer:</u> The weight of the object is 29.4 N

<u>Explanation:</u>

To calculate the weight of the object, we use the equation:

W=m\times g

where,

m = mass of the object = 3 kg

g = acceleration due to gravity = 9.8m/s^2

Putting values in above equation, we get:

W=3kg\times 9.8m/s^2\\\\W=29.4N

Hence, the weight of the object is 29.4 N

6 0
3 years ago
A 40 kg slab rests on a frictionless floor. A 10 kg block rests on top of the slab (Fig. 6-58). The coefficient of static fricti
vovikov84 [41]

Answer:

<u>\text { The "resulting action" on the slab is } 0.98 \mathrm{m} / \mathrm{s}^{2}</u>

Explanation:

Normal reaction from 40 kg slab on 10 kg block

M × g  = 10 × 9.8 = 98 N  

Static frictional force = 98 × 0.7 N

Static frictional force = 68.6 N is less than 100 N applied  

10 kg block will slide on 40 kg slab and net force on it  

= 100 N - kinetic friction  

=100-(98 \times 0.4)\left(\mu_{\text {kinetic }}=0.4\right)

= 100 - 39.2

= 60.8 N

10 \mathrm{kg} \text { block will slide on } 40 \mathrm{kg} \text { slab with, } \frac{\mathrm{Net} \text { force }}{\text { mass }}

10 \mathrm{kg} \text { block will slide on } 40 \mathrm{kg} \text { slab with }=\frac{60.8}{10}

10 \mathrm{kg} \text { block will slide on } 40 \mathrm{kg} \text { slab with }=6.08 \mathrm{m} / \mathrm{s}^{2}

\text { Frictional force on 40 kg slab by 10 kg block, normal reaction \times \mu_{kinetic } }

Frictional force on 40 kg slab by 10 kg block = 98 × 0.4  

Frictional force on 40 kg slab by 10 kg block = 39.2 N  

40 \mathrm{kg} \text { slab will move with } \frac{\text { frictional force }}{\text { mass }}

40 \mathrm{kg} \text { slab will move with }=\frac{39.2}{40}

40 kg slab will move with = 0.98 \mathrm{m} / \mathrm{s}^{2}

\text { The "resulting action" on the slab is } 0.98 \mathrm{m} / \mathrm{s}^{2}

3 0
3 years ago
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