Answer:
hmax=81ft
Explanation:
Maximum height of the object is the highest vertical position along its trajectory.
The vertical velocity is equal to 0 (Vy = 0)

we isolate th (needed to reach the maximum height hmax)

The formula describing vertical distance is:

So, given y = hmax and t = th, we can join those two equations together:


if we launch a projectile from some initial height h all you need to do is add this initial elevation


Approximately 150-200 species.
The wavelength of the radio waves is 3.04 cm.
<h3>Calculation:</h3>
λf = c
λ = c/f
where,
λ = wavelength
c = speed of light
f = frequency
Given,
f = 98.6 MHz = 98.6 × 10⁶
c = 3 × 10⁸
To find,
λ =?
Put the values in the formula,
λ = c/f
λ = 3 × 10⁸/98.6 × 10⁶
= 0.0304 × 10² m
= 3.04 cm
Therefore, the wavelength of the radio waves is 3.04 cm.
Learn more about the calculation of wavelength here:
brainly.com/question/8422432
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10m long is the right answer or 16
Answer:
A. The photographer will get to the jeep before the rhinocerous
Explanation:
Δv = Δd/Δt
we can rearrange for time
Δt = Δd/Δv
For the photographer:
Distance is 10m and moves at 6m/s
Δt = 10m/6m/s
Δt = 1.67s
For the rhinocerous
Distance is 16m and moves at 8m/s
Δt = 16m/8m/s
Δt = 2.00s
The distances were to get to the jeep, the photographer makes it to the jeep in a shorter amount of time than the rhino