Consider the function

, which has derivative

.
The linear approximation of

for some value

within a neighborhood of

is given by

Let

. Then

can be estimated to be

![\sqrt[3]{63.97}\approx4-\dfrac{0.03}{48}=3.999375](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B63.97%7D%5Capprox4-%5Cdfrac%7B0.03%7D%7B48%7D%3D3.999375)
Since

for

, it follows that

must be strictly increasing over that part of its domain, which means the linear approximation lies strictly above the function

. This means the estimated value is an overestimation.
Indeed, the actual value is closer to the number 3.999374902...
change,c = 20 - p
so in Excel for example
put 20 in column a
put 11.59, 17.50 etc in column b
in column c put the equation '=20 - b1'
Answer:
pours 3 gallons of paint equally into 5 cans. How many gallons of paint will there be in each can? ... Did you divide to get the answer? ... If two gallons of paint is needed to paint a 40 sq meter wall, how many gallons of paint ... Hamza bought 8 gallons of brown paint to paint his kitchen and dining room
Answer:
0.53
Step-by-step explanation:
53/100<60/100