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2 years ago

Find the LCM of 13 and 52. LCM = .

Mathematics

2 answers:

AleksAgata [21]2 years ago

8 0

Answer:

Step-by-step explanation:

13 , 52

Here 13 is a prime number. So, check if 52 is a multiple of 13.

Yes, 13*4 = 52

LCM = 52

Tpy6a [65]2 years ago

3 0

Answer:

Step-by-step explanation:

L.C.M of 13 and 52 is,

13 | 13 , 52

4 | 1 , 4

| 1 , 1

L.C.M = 13 x 4 = 52

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15% of what number is equal to 9

just olya [345]

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2 years ago

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irina [24]

First graph it

Maximum height is the y coordinate of vertex

(2,144)

Max height

144m

Time is the x coordinate of vertex

y is 0

$\\ \rm\Rrightarrow -16t^2+64t+80=0$

x intercepts are the solutions

(-1,0)U(5,0)

Take it positive

t=5s

put in function

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8 0

2 years ago

Triangle RST has vertices R(2, 0), S(4, 0), and T(1, –3). The image of triangle RST after a rotation has vertices R'(0, –2), S'(

sleet_krkn [62]

Answer with explanation:

Pre -image= Vertices of Δ R ST=R(2, 0), S(4, 0), and T(1, –3)

Image of Δ R ST after rotation= R'(0, –2), S'(0, –4), and T'(–3, –1)

Pre-Image lies in Fourth Quadrant and Image lies in Third Quadrant.

If triangle is rotated by different angles in anticlockwise direction,then

$(a,b)_{90^{\circ}}=(-b, a)\\\\(a,b)_{180^{\circ}}=(-b, -a)\\\\(a,b)_{270^{\circ}}=(b, -a)$

If triangle is rotated by different angles in Clockwise direction,then

$(a,b)_{90^{\circ}}=(b, -a)\\\\(a,b)_{180^{\circ}}=(-b, -a)\\\\(a,b)_{270^{\circ}}=(-b, a)$

⇒→So, Pre image that is ,Δ R ST having vertices ,R(2, 0), S(4, 0), and T(1, –3) when rotated by either 90° in clockwise direction or by 270°, in anticlockwise Direction to get Image Δ R' S'T' having vertices R'(0, –2), S'(0, –4), and T'(–3, –1) .