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3 years ago

10 points for answering! What is the answer to 13, 14, and 15?

Mathematics

1 answer:

ki77a [65]3 years ago

4 0

Step-by-step explanation:

$\implies\sf{ {x}^{2} = 144 } \\ \\ \implies\sf{ x = \pm \sqrt{144} } \\ \\ \implies\sf{ x = \pm 12 }$

$\implies\sf{ {x}^{2} = \dfrac{25}{289} } \\ \\ \implies\sf{ x = \pm \sqrt{ \frac{25}{289} } } \\ \\ \implies\sf{ x = \pm \frac{5}{17} }$

$\implies\sf{ {x}^{3} = 216 } \\ \\ \implies\sf{ x = \sqrt[3]{216} } \\ \\ \implies\sf{ x = 6 }$

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A food distributor is being sued for racial discrimination because 12% of newly hired candidates are not white when 53% of all a

Musya8 [376]

Answer:

Check Explanation

Step-by-step explanation:

A) The null hypothesis would be that the proportion of newly hired candidates that are not white is not significantly different from the proportion of the applicants that are not white & there is no significant evidence that the company's hiring practices are discriminatory.

Mathematically,

H₀: μ₀ = 0.53

And the alternative hypothesis would be that there is a significant difference between the proportion of newly hired candidates that are not white is not significantly different from the proportion of the applicants that are not white. More specifically, that the proportion of newly hired candidates that are not white is significantly less than the proportion of applicants that are not white & there is significant evidence that the company's hiring practices are indeed discriminatory.

Mathematically,

Hₐ: μ₀ < 0.53

B) The two errors that can come up in this hypothesis testing include -

Type I error: We reject the null hypothesis because we obtain that the proportion of newly hired candidates that are not white is significantly less than the proportion of applicants that are not white and conclude that there is indeed significant evidence that the company's hiring practices are discriminatory when in reality, there is no significant difference and hence, no discrimination.

Type II error: We accept the null hypothesis (fail to reject the null hypothesis) because we obtained that there is no significant difference between the proportion of newly hired candidates that are not white & th proportion of applicants that are not white and conclude that there is no discrimination in the company's hiring practices when in reality, there is significant difference in the stated proportions above and significant evidence that there is indeed significant evidence that the company's hiring practices are discriminatory.

C) The power of the test increases as the significance level reduces. This is because t-statistic increases as significance level reduces.

D) The standard error of the mean used in computing the t-score is given as

σₓ = (σ/√n)

It is evident that as the value of n increases, the standard error reduces and this widens the effect of the test, hence, the power of the test increases.

Hope this Helps!!!

7 0

3 years ago

Tom was selling his old games. He started out with 57 but sold 37 of them. He put the rest in boxes with 5 games in each. How ma

eduard

Answer:

Tom started out with 57 games but sold 37 of them.

=> Now, Tom has: 57 - 37 =20 games

He put the rest in boxes with 5 games in each.

=> The number of boxes: 20/5 = 4 box

Hope this helps!

8 0

3 years ago

NO LINKS!!

dexar [7]

Answer: Anything between 0 and 10, excluding both endpoints.

In terms of symbols we can say 0 < w < 10 where w is the width.

===================================================

Explanation:

You could do this with two variables, but I think it's easier to instead use one variable only. This is because the length is dependent on what you pick for the width.

w = width

2w = twice the width

2w-5 = five less than twice the width = length

So,

width = w
length = 2w-5

which lead to

area = length*width

area = (2w-5)*w

area = 2w^2-5w

area < 150

2w^2 - 5w < 150

2w^2 - 5w - 150 < 0

To solve this inequality, we will solve the equation 2w^2-5w-150 = 0

Use the quadratic formula. Plug in a = 2, b = -5, c = -150

$w = \frac{-b\pm\sqrt{b^2-4ac}}{2a}\\\\w = \frac{-(-5)\pm\sqrt{(-5)^2-4(2)(-150)}}{2(2)}\\\\w = \frac{5\pm\sqrt{1225}}{4}\\\\w = \frac{5\pm35}{4}\\\\w = \frac{5+35}{4} \ \text{ or } \ w = \frac{5-35}{4}\\\\w = \frac{40}{4} \ \text{ or } \ w = \frac{-30}{4}\\\\w = 10 \ \text{ or } \ w = -7.5\\\\$

Ignore the negative solution as it makes no sense to have a negative width.

The only practical root is w = 10.

If w = 10 feet, then the area = 2w^2-5w results in 150 square feet.

----------------------

Based on that root, we need to try a sample value that is to the left of it.

Let's say we try w = 5.

2w^2 - 5w < 150

2*5^2 - 5*5 < 150

25 < 150 ... which is true

This shows that if 0 < w < 10, then 2w^2-5w < 150 is true.

Now try something to the right of 10. I'll pick w = 15

2w^2 - 5w < 150

2*15^2 - 5*15 < 150

375 < 150 ... which is false

It means w > 10 leads to 2w^2-5w < 150 being false.

Therefore w > 10 isn't allowed if we want 2w^2-5w < 150 to be true.

4 0

2 years ago

WHOEVER ANSWERS CORRECTLY I'LL GIVE BRAINLIEST!!!!!!!!!!!

Likurg_2 [28]

Answer:

answer what ?

Step-by-step explanation:

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2 years ago

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Plz help. Will give brainliest

diamong [38]

Answer:

17.1

Step-by-step explanation:

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3 years ago

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