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3 years ago

Find the value of x in the triangle shown below.

Mathematics

1 answer:

MrMuchimi3 years ago

5 0

Answer: 102 degrees

Step-by-step explanation:

This is an isosceles triangle because two of the sides are the same length which means that two angles are congruent as well.

180-(2(39))

=180-(78)

=102

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3 years ago

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2 years ago

Water weighs 62.4 pounds per cubic foot. How much does the water in a tank that measures 7 ft × 4 ft × 9 in, weigh?

andriy [413]

Answer:

1,310 lb

Explanation:

1) Calculate the volume of the water in the tank.

Area of the base of the tank: B = 7 ft × 4 ft = 28 ft²

Height of the tank: H = 9 in = 9 in × 1 ft / 12 in = 0.75 ft

Volume of the tank: V = area of the base × height = B × H = 28 ft² × 0.75 ft = 21 ft³.

2) Calculate the weight of 21 ft³ of water.

Since this is not a chemistry question but a math question, I will not use the fomula of density but set a proportion with one unknown:

62.4 lb / 1 ft³ = x / 21 ft³

Solve for x:

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So, rounding to the next integer, the water in the tank weighs 1,310 pounds, when it is full.

6 0

3 years ago

Read 2 more answers

Find the altitude of triangle whose vertex is a(1,-2) and the equation of the base is X+y=3.

Sophie [7]

Answer:

$2\sqrt {2}$

Step-by-step explanation:

Distance From a Point to a Line

Given a line with an equation :

ax + by + c = 0

And the point $(x_0,y_0)$

The distance from the line to the point is given by

$\displaystyle d=\frac {|ax_{0}+by_{0}+c|}{\sqrt {a^{2}+b^{2}}}$

The triangle has a vertex at (1,-2) and the base lies on the equation

x + y = 3

Rearranging:

x + y - 3 = 0

The altitude of the triangle is the distance from the point to the line.

The values to use in the formula of the distance are: a=1, b=1, c=-3, xo=1, yo=-2:

$\displaystyle d=\frac {|1*1+1*(-2)-3|}{\sqrt {1^{2}+1^{2}}}$

$\displaystyle d=\frac {|1-2-3|}{\sqrt {2}}$

$\displaystyle d=\frac {4}{\sqrt {2}}$

Rationalizing:

$\displaystyle d=\frac {4}{\sqrt {2}}\cdot\frac{\sqrt {2}}{\sqrt {2}}$

$\displaystyle d=2\sqrt {2}$

The altitude of the triangle is $\mathbf{4\sqrt {2}}$

6 0

3 years ago